Identify the gcf of 10x4y3 â 5x3y2 + 20x2y. 10x2y 10x3y 5x2 5x2y

The pilgrims and indians had a feast a big feast there was 10 more pilgrims than indians there were 150 people in all how many p

Alexeev081 [22]

X + 10 = 80 pilgrims are in the feast

5 0

3 years ago

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

4 0

3 years ago

I don't like word problems, i need help with this guys

alina1380 [7]

Okay so first we want to find out how many cans one person uses a year. To find this we divide 16,801 by 53 and we get 317 cans a year. Using this we can find how many cans 1,694,000 people use a year by multiplying the people by 317. You get 536,998,000 cans a year, which is your answer.

7 0

3 years ago

A square field has an area of 144 metres squared. If Andrea walked 10 times around this field, what distance did she cover?

Novosadov [1.4K]

Answer:

480m

Step-by-step explanation:

First we have to find the perimeter of the field.

We know that the area is 144m and that the field is a square.

Since a squares sides are all equal, we can do $\sqrt{144}$ , which is 12m.

So, one side of the field is 12m; now we just find the perimeter which is easy since its a square. 12*4=48m

If Andrea walked around it 10 times, then we just multiply the perimeter by 10

48*10=480m

7 0

2 years ago

A candy distributor needs to mix a 40% fat-content chocolate with a 60% fat-content chocolate to create 100 kilograms of a 56% f

max2010maxim [7]

Solving a system of equations we can see that:

They need to use 80kg of the 60% chocolate and 20kg of the 40% chocolate.

<h3>How to find how much of each candy needs to be used?</h3>

Let's define the variables:

x = kilograms of the 40% chocolate.
y = kilograms of the 60% chocolate.

They want to make 100kg, then:

x + y = 100

And the concentration must be of the 56%, then we can write:

x*0.4 + y*0.6 = (100)*0.56 = 56

Then we have a system of equations:

x + y = 100

x*0.4 + y*0.6 = 56

To solve this, we can isolate x on the first equation to get:

x = 100 - y

Now replace that in the other equation:

(100 - y)*0.4 + y*0.6 = 56

40 + y*0.2 = 56

y*0.2 = 16

y = 16/0.2 = 80

This means that they need to use 80kg of the 60% chocolate and the other 20kg of the 40% chocolate.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

8 0

1 year ago