You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
Answer:
2
Step-by-step explanation:
6 metros multiplicado por 2 metros o 3 metros multlipicado 4 metros
FIRST PROBLEM AS GENIUS!!!
The 45-45-90 triangle theorem states that each leg equals x, and the hypotenuse equals

. Using this, we can find that the height is 10. Take the average of the lengths to get l = 27.
The area = 270.
1)100 or A
Angle = |30*H - (11/2)*M|, where H is the hours hand and M is the minutes hand
in this case: H = 4, M= 40
30*4 - (11/2)*40 = 120 - 220 = -100 = |-100| = 100
2)x=4y or C
If you plug in 0,0 you will get 0=4×0 or 0,0