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maks197457 [2]
3 years ago
9

What is the length of DE in the right triangle below

Mathematics
1 answer:
liraira [26]3 years ago
8 0

The answer is B

Step-by-step explanation:

As shown in the given figure, ΔDEF is a right-angles triangle, where ∠DFE = 90°, DF = 15 units and EF = 20 units.

We are to find the length of DE.

ΔDEF is right-angled at ∠DFE.

So, using Pythagoras theorem, we have

\begin{lgathered}DE^2=DF^2+EF^2\\\\\Rightarrow DE^2=15^2+20^2\\\\\Rightarrow DE^2=225+400\\\\\Rightarrow DE^2=625\\\\\Rightarrow DE^2=25^2\\\\\Rightarrow DE=25.\end{lgathered}

DE

2

=DF

2

+EF

2

⇒DE

2

=15

2

+20

2

⇒DE

2

=225+400

⇒DE

2

=625

⇒DE

2

=25

2

⇒DE=25.

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The simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.

<h3>What is the simplified form of an equation?</h3>

The simplified form of an equation is the simplest way of expressing the equation, by applying the required operations of mathematics.

The equation provided in the problem is,

2\sqrt{18}+3\sqrt{2}+\sqrt{162}

Let the simplified form of the above expression is <em>n. </em>Thus,

n=2\sqrt{18}+3\sqrt{2}+\sqrt{162}

Rewrite the equation to solve it further as,

n=2\sqrt{3\times3\times2}+3\sqrt{2}+\sqrt{9\times9\times2}\\n=2\sqrt{3^2\times2}+3\sqrt{2}+\sqrt{9^2\times2}

The square of the term cancel out the square root of it. Thus,

n=2\times3\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=6\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=(6+3+9)\sqrt{2}\\n=18\sqrt{2}

Thus, the simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.

Learn more about the simplified form here;

brainly.com/question/1597694

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Step-by-step explanation:

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From the question, we can see that the initial value is 22

Kindly recall that we can write 1.77 as 1+ 0.77

Now 0.77 is same as 77/100 which simply imply77%

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Consider triangle WBG, where points W, B and G represent Weather Station, Balloon and Ground, respectively. This triangle is right with right angle at vertex G. The legs of this triangle are GB and GW, the hypotenuse is BW.

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