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3 years ago

7

ORDERING REAL NUMBERS

2 answers:

Bess [88]3 years ago

4 0

3/25, 0.1, -√86, -9.34

grigory [225]3 years ago

3 0

3/25 = 0.12
-√86 = -9.27

Least to greatest: -9.34, -√86, 0.1, 0.12

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A n =−1+3(n−1) an=−1+3(n−1) what is the 55 term in the sequence

Sindrei [870]

ANSWER

$a_{55}=161$

EXPLANATION

The general term for the sequence is

$a_n=-1+3(n-1)$

To find the 55th term, we have to substitute
$n = 55$
in to the general term and simplify.

This implies that,

$a_{55}=-1+3(55-1)$

$a_{55}=-1+3(54)$

$a_{55}=-1+162$

$a_{55}=161$

Therefore the 55th term is 161.

8 0

3 years ago

Which expression has a value of 15 when n = 7? 43 minus 5 n 3 n minus 5 6 n minus 28 19 minus StartFraction 28 Over n EndFractio

andrey2020 [161]

Answer:

$19-\dfrac{28}{n}$ is the expression with value of 15 when n = 7.

Step-by-step explanation:

To find the expression whose value is 15, substitute the value of n = 7 in each given expression.

Expression 1:

$43-5n$

Substituting the value of n,

$43-5\left(7\right)$

Simplifying,

$43-35=8$

Since the value of the expression is 8 which is not equal 15.

Hence expression $43-5n$ does not have value of 15 when n = 7.

Expression 2:

$3n-5$

Substituting the value of n,

$3\left(7\right)-5$

Simplifying,

$21-5=16$

Since the value of the expression is 16 which is not equal 15.

Hence expression $3n-5$ does not have value of 15 when n = 7.

Expression 3:

$6n-28$

Substituting the value of n,

$6\left(7\right)-28$

Simplifying,

$42-28=14$

Since the value of the expression is 14 which is not equal 15.

Hence expression $6n-28$ does not have value of 15 when n = 7.

Expression 4:

$19-\dfrac{28}{n}$

Substituting the value of n,

$19-\dfrac{28}{7}$

Simplifying,

$19-4=15$

Since the value of the expression is 15 which is equal 15.

Hence expression $19-\dfrac{28}{n}$ has the value of 15 when n = 7.

4 0

3 years ago

Read 2 more answers

Protozoa are single-celled organisms. Paramecium aurelia is one type of protozoan. The number of paramecium aurelia doubles ever

Sphinxa [80]

Answer:

16 days

Step-by-step explanation:

Given that:

Number of paramecium Aurelia doubles every 1.25days

5 days ago ; number of paramecium Aurelia = 1

How many are there now?

Using the relation :

Multiplier^(total number of days / time it takes to multiply)

Multiplier = doubles = 2

Total number rof days =. 5

Time it takes to. Multiply = 1.25

The formula becomes :

Number(n) of ptotozoan in 5days is given by 2^(5/1.25)

n = 2^(5/1.25)

n = 2^4

n = 2 * 2 * 2 * 2 =. 16

5 0

3 years ago

Answer this, please! Anybody

Juliette [100K]

Answer:

1/4 and 1/8 which shold multiply

Step-by-step explanation:

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3 years ago

What is the slope of the line that goes through the points (-3, 8) and (0, 23)?

Kipish [7]

Answer:

5

Step-by-step explanation:

(-3, 8) and (0, 23)

m=(y2-y1)/(x2-x1)

m=(23 - 8)/(0+3)

m=(15)/3

m = 5

5 0

3 years ago

Read 2 more answers