The area of a field shaped like a right triangle is 750yd^2.One leg of the field is fenced with wood costing $5/yd. the remainde
r of the perimeter of the field is fenced with steel costing $10/yd. the perimeter of the field is 150yd. The total cost of the fencing is $1200. A- What is the length of the leg fenced with wood?
B- What is the length of the leg fenced with steel?
Assume that a and b = the two legs of the right triangle. c = the hypotenuse.
The area of the right triangle is 750 yd², therefore (1/2)*a*b = 750 ab = 1500 (1)
The perimeter is 150yd, therefore a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore 5a + 10b + 10c = 1200 or a + 2b + 2c = 240 (3)
From (2), obtain c = 150 - a - b (4)
Substitute (4) into (3) a + 2b + 2(150 - a - b) = 240 -a + 300 = 240 a = 60
From (1), obtain 60b = 1500 b = 25
From (4), obtain c = 150 - 60 - 25 = 65
Answer: A. The length of the leg fenced with wood is 60 yd. B. The length of the leg fenced with steel is 25 yd.
If 3 inches tall per hour, and you need to find the amount of rain in 24 hours, you just need to multiply the number of inches per hour by the number of hours required (24 hours):
