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3 years ago

Please help me please!!

Mathematics

1 answer:

Tpy6a [65]3 years ago

3 0

Answer:

Extracting out that inner right angle.

Hypotenuse = 8

Height = h

Adjacent :

$= \frac{10}{5} = 2$

Height, h :

${ \tt{h = \sqrt{ {8}^{2} - {5}^{2} } }} \\ { \tt{h = \sqrt{64 - 25} }} \\ { \tt{h = \sqrt{39} }} \\ the \: height \: is \: { \boxed{6.2}} \: units$

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Pleaseeeee help im horrible at math

Murljashka [212]

Answer:

The Answer is gonna be D. 2

This is the right Answer:3

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3 years ago

Read 2 more answers

A student has a savings account earning 3% simple interest. She must pay $1200 for first-semester tuition by September 1 and $12

Bingel [31]

Using simple interest, it is found that she needs to earn $2,391.07 during the summer.

<h3>Simple Interest</h3>

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

A(t) = A(0)(1 + rt)

In which:

A(0) is the initial amount.

r is the interest rate, as a decimal.

For this problem, the objective is to have <u>$1200 in 3 months = 0.25 years</u>, hence the parameters are given as follows:

A(0.25) = 1200, t = 0.25, r = 0.03.

Hence we have to solve for A(0):

A(0)(1 + 0.03 x 0.25) = 1200

A(0) = 1200/(1 + 0.03 x 0.25)

A(0) = $1,191.07.

She also needs to earn $1,200 to pay the first-semester bill on time, hence:

1200 + 1191.07 = $2,391.07.

She needs to earn $2,391.07 during the summer.

More can be learned about simple interest at brainly.com/question/16646150

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3 0

1 year ago

Please Identify the congruent triangles in the figure.

Tpy6a [65]

The missing steps are each right angles and $\angle R \cong \angle O$ .

Solution:

Step 1: Given data:

$\overline {P Q} \cong \overline{M N}$

$\overline{Q R} \cong \overline{N O}$

$\overline{P R} \cong \overline{M O}$

Step 2: In the two polygons,

$\angle Q =90^\circ$ and $\angle N =90^\circ$

$\angle Q \cong \angle N$ (Each right angle)

Step 3: Given

$\angle P \cong \angle M$

Step 4: By third angle theorem,

If two angles in one triangle are congruent to the two angles in the other triangle, then the third angles in the triangles also congruent.

$\angle R \cong \angle O$

Step 5: By the definition of congruent polygons,

If two same shape polygons have all the angles are congruent and all the corresponding sides are congruent then the polygons are congruent.

Hence $\Delta P Q R \cong \Delta M N O$ .

Therefore the missing steps are each right angles and $\angle R \cong \angle O$ .

5 0

3 years ago

I need the answer for part b

Softa [21]

Answer:

4/4

Step-by-step explanation:

1/4 plus 1/4 plus 2/4 is 4/4

4 0

2 years ago

PLEASE HELP ITS EXTRA CREDIT AND I COULD REALLY USE IT !! BEING TIMED! for each of the following statements, determine if the st

bogdanovich [222]

A. True. We see this by taking the highest order term in each factor:

$f(x) = -3x(x-5)^3(x+2)^2 = -3x (x^3 + \cdots) (x^2 + \cdots) = -3x^{\boxed{6}} + \cdots$

B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.

C. False. f(x) = 0 only for x=0, x = 5, and x = -2.

D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.

E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).

F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.

8 0

2 years ago