Please help me please!!

Mathematics

1 answer:

Tpy6a [65]3 years ago

3 0

Answer:

Extracting out that inner right angle.

Hypotenuse = 8

Height = h

Adjacent :

$= \frac{10}{5} = 2$

Height, h :

${ \tt{h = \sqrt{ {8}^{2} - {5}^{2} } }} \\ { \tt{h = \sqrt{64 - 25} }} \\ { \tt{h = \sqrt{39} }} \\ the \: height \: is \: { \boxed{6.2}} \: units$

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54.85 rounded to the nearest 1/10th percent

Iteru [2.4K]

Answer:

54.9

Step-by-step explanation:

You always round up if its 0.5 or anything .5

54.58 broken down:

The 5 is the Tens place

The 4 is the Ones place

The 8 is the Tenth place (what the question is asking for)

The 5 is the Hundredths place.

:) Hope this helps! Please mark brainliest! :)

8 0

3 years ago

If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3

yulyashka [42]

Hello,

$L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\$