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elixir [45]
3 years ago
7

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

nd C′(15, 0). The origin is the center of dilation. What is the scale factor of the dilation?
Mathematics
1 answer:
Vesnalui [34]3 years ago
3 0

Answer:

2.5

Step-by-step explanation:

A triangle ABC with vertices A(0, 0), B(0, 4), and C(6, 0) is dilated to form a triangle A'B'C' with vertices A′(0, 0), B′(0, 10), and C′(15, 0). If the center of dilation is point A or A' (the origin), then

\dfrac{A'B'}{AB}=\dfrac{A'C'}{AC}.

Since

  • AB=4;
  • A'B'=10;
  • AC=6;
  • A'C'=15,

then the scale factor of the dilation is

k=\dfrac{10}{4}=\dfrac{15}{6}=2.5.

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