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3 years ago

I Neeeeddddddd Thhhhhiiiiissssss!

Mathematics

1 answer:

crimeas [40]3 years ago

4 0

The correct answer is A. It satisfies the top equation but not the bottom equation.

This can be found by plugging in the given x and y values to the system, as seen in the attached picture.

I hope this helps! :)

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Can someone please help as soon as possible

maks197457 [2]

The answer is A because it starts at the origin

7 0

3 years ago

Read 2 more answers

Dave works two jobs. He works at the grocery store making $12 per hour and works at the car wash making $15 per hour. If he work

vladimir2022 [97]

Answer:

11 hours

Step-by-step explanation:

let he works at first store x hours and at car wash y hours. Then

x+y=25

multiply by 4

4x+4y=100 ...(1)

12x+15y=333

divide by 3

4x+5y=111 ... (2)

(2)-(1) gives

y=111-100=11

8 0

3 years ago

WHAT IS THE ANSWER FOR THIS?!? I WILL MARK BRAINLIEST!!!

Dimas [21]

1. it’s saying 2-6 which is -4

2. it’s saying -6-5 which is -11

6 0

3 years ago

Please someone help me to prove this.

dem82 [27]

<h3>Answer :</h3>

We know that,

$\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}$

$\dag\bf\:sin2A=2sinA\:cosA$

___________________________________

Now, Let's solve !

$\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}$

$\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}$

$\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}$

$\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}$

$\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}$

$\leadsto\:\bf{tan(A+B)}$

5 0

3 years ago

Read 2 more answers

Boris Heban is single and pays into an HMO. The total cost is $8,190 annually, and the employer pays 90 percent of the total cos

adell [148]

So Boris has to pay:
10% * 8190 = 819
50% * 662 = 331
50% * 188 = 94

so in total he pays: 819 + 331 + 94 = 1244

deducted each week is (52 weeks in a year):
1244/52 = 23.92

so each week $23.92 are deducted from his paycheck

8 0

3 years ago