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zalisa [80]
3 years ago
8

Solve the system of equations 5x + 3y = -2 3x + 2y = -1

Mathematics
1 answer:
Drupady [299]3 years ago
7 0

Answer:

Step-by-step explanation:

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IF U ANSWER THIS U ARE SWAG!!!
Nitella [24]
Where is the triangle?
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3 years ago
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Determine if the two figures are congruent and explain your answer using transformations.
IRISSAK [1]

Answer:

Comparing each pair of lines,

AB and EF,

BC and FG,

CD and GH,

DA and HE.

For, AB and EF,

If we take a look at both the lines they are the mirror image of each other, the distance between point A and B is 1 unit upwards, and 2 unit sidewise, similarly between point E and F the distance is 1 unit upwards, and 2 unit sidewise. therefore, the length of both the lines is the same.

Also, we can use the formula, for the distance between two points on a coordinate plane,

,

As we can see in the image,

A = (-1, 1),

B = (-3, 2),

C = (-4, 4),

D = (-2, 6),

E = (2, 0),

F = (4, 1),

G = (5, 3),

H = (3, 5),

Solving using the formula,

AB = EF = √5,

BC = FG = √5,

CD = GH = √8,

DA = HE = √26,

Therefore, the length of all the sides of the polygon are the same,

Hence, the two figures are congruent.

Step-by-step explanation:

7 0
2 years ago
The perimeter of a notebook is 44 inches the notebook is 10 inches wide how tall is it?
tatyana61 [14]
Answer=36inches tall

Explanation= 44+10= 54
90-54=36in
5 0
3 years ago
Shirts are 5% off. The original price of one shirt is $15. What is the total cost, in dollars, of a shirt at the sale price, inc
Juliette [100K]

Answer:

$15.75

Step-by-step explanation:

\frac{y}{15} :\frac{5}{100}

y × 100 = 5 × 15

100y = 75

100y ÷ 100 = 75 ÷ 100

y = 0.75

$15 - $0.75

$14.25

\frac{y}{15} :\frac{10}{100}

y × 100 = 10 × 15

100y = 150

100y ÷ 100 = 150 ÷ 100

y = 1.5

$14.25 + $1.50

$15.75

8 0
3 years ago
What is the following product?
Leona [35]

Answer:

First option: 6y^2sqrt(10) + 12sqrt(5y)

Step-by-step explanation:

3sqrt(10) * (2y^2 + 2sqrt(2y)

= 6y^2sqrt(10) + 6sqrt(20y)

= 6y^2sqrt(10) + 12sqrt(5y)

3 0
3 years ago
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