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Leni [432]
3 years ago
10

The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately 0.7. What is the probability

that, in a randomly selected sample of four citizen-entities, all of them are of pension age?
Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer: 0.2401

Step-by-step explanation:

The binomial distribution formula is given by :-

P(x)=^nC_xp^x(1-p)^{n-x}

where P(x) is the probability of x successes out of n trials, p is the probability of success on a particular trial.

Given : The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately: p =0.7.

Number of trials  : n= 4

Now, the required probability will be :

P(x=4)=^4C_4(0.7)^4(1-0.7)^{4-4}\\\\=(1)(0.7)^4(1)=0.2401

Thus, the probability that, in a randomly selected sample of four citizen-entities, all of them are of pension age =0.2401

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1.2  The area of <em>cardboard</em> required to make a single <u>milk</u> carton is  332.6 cm^{2}.

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The <u>volume</u> of a given <u>shape</u> is the amount of <em>substance</em> that it can contain in a 3-dimensional <em>plane</em>. Examples of <u>shapes</u> with volume include cubes, cuboids, spheres, etc.

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                                                         = 6 x 6 x 10

                                                        = 360

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1.2 The <em>total area</em> of<em> cardboard </em>required to make a single<u> milk</u> carton can be determined as follows:

i. <u>Area</u> of the <u>rectangular</u> surface = length x width

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ii. <u>Area</u> of the <u>square</u> surface = side x side = s²

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 <u>Area</u> of the <u>square</u> surface = 36 cm^{2}

iii. There are four <em>semicircular</em> <u>surfaces</u>, this implies a total of 2 <u>circles</u>.

<em>Area</em> of a <u>circle</u> = \pi r^{2}

where r is the <u>radius</u> of the <u>circle</u>.

Total <u>area</u> of the <em>semicircular</em> surfaces = 2 \pi r^{2}

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Total <u>area</u> of the <em>semicircular</em> surfaces = 56.6 cm^{2}

Therefore, total area of  <em>cardboard</em> required = 240 + 36 + 56.6

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The <u>area</u> of <em>cardboard</em> required to make a single <em>milk carton</em> is  332.6 cm^{2}.

1.3 Since,

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360 cm^{3} = x

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The <u>cost</u> of filling the 200 <u>cartons</u> is R 86.40.

For more clarifications on the volume of a cuboid, visit: brainly.com/question/20463446

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