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Leni [432]
3 years ago
10

The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately 0.7. What is the probability

that, in a randomly selected sample of four citizen-entities, all of them are of pension age?
Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer: 0.2401

Step-by-step explanation:

The binomial distribution formula is given by :-

P(x)=^nC_xp^x(1-p)^{n-x}

where P(x) is the probability of x successes out of n trials, p is the probability of success on a particular trial.

Given : The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately: p =0.7.

Number of trials  : n= 4

Now, the required probability will be :

P(x=4)=^4C_4(0.7)^4(1-0.7)^{4-4}\\\\=(1)(0.7)^4(1)=0.2401

Thus, the probability that, in a randomly selected sample of four citizen-entities, all of them are of pension age =0.2401

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Answer:

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B) 1.96

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Step-by-step explanation:

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H_o : \mu  = 10

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Zo = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}

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from 1 eq we get

\pi (\left | Zc \right |) = P(Zo

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B) significance level  \alpha = 0.05

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\pi (\left | Zc \right |) = P(Zo

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