Answer:
The ways in which he can make selection = 
Step-by-step explanation:
Student is having a list of
books.
Assuming that the student can't read the same book twice.
The student has
choices to make for an outside reading requirement,for his 1st choice, he had
books to choose from; for his 2nd, he has
books left to choose from therefore the total permutations of his choices are 
So the total ways in which the student can make his selection = 
Sub 2 for x in j(x) and evalueate
then sub that result for x in h(x)
j(2)=-2(2)
j(2)=-4
now sub-4 for x in h(x)
h(-4)=5(-4)-3
h(-4)=-20-3
h(-4)=-23
answer is -23
Altogether balls 4+2+3+5=14
P(red)=4/14=2/7
P(green)=2/14
P(yellow)=3/14
P(blue)=5/14
because it goes with replacement these probabilities are constant
Answer:
I believe it's D. (3,4)
Step-by-step explanation:
A equals 3, and after plugging that in and simplifying, you're left with B=4.
<em>Hope this helps!</em>
The letter weighted 7 ounces