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vladimir2022 [97]
3 years ago
5

1) Find the length of point A(-3,1) and B(2,6). Leave your answer in RADICAL FORM ONLY.

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer: The length of point A(-3,1) and B(2,6) is 5\sqrt{2}\text{ units} .

Step-by-step explanation:

We know that the distance between the two points (a,b) and (c,d) is given by :-

d=\sqrt{(a-c)^2+(b-d)^2}

Given points = A(-3,1) and B(2,6)

Therefore the distance between the points A(-3,1) and B(2,6) is given by :-

d=\sqrt{(-3-2)^2+(1-6)^2}\\\\\Rightarrow\ d=\sqrt{(-5)^2+(-5)^2}\\\\\Rightarrow\ d=\sqrt{25+25}\\\\\Rightarrow\ d=\sqrt{50}\\\\\Rightarrow\ d=\sqrt{25\times2}\\\\\Rightarrow\ d=\sqrt{5^2\times2}\\\\\Rightarrow\ d=5\sqrt{2}\text{ units}

Hence, the length of point A(-3,1) and B(2,6) is 5\sqrt{2}\text{ units} .

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SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given set of values

321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320

STEP 2: Write the formula for calculating the Standard deviation of a set of numbers

\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ where\text{ }x_i\text{ are data points,} \\ \bar{x}\text{ is the mean} \\ \text{n is the number of values in the data set} \end{gathered}

STEP 3: Calculate the mean

\begin{gathered} \bar{x}=\frac{\sum ^{}_{}x_i}{n} \\ \bar{x}=\frac{\sum ^{}_{}(321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320)}{20} \\ \bar{x}=\frac{8453}{20}=422.65 \end{gathered}

STEP 4: Calculate the Standard deviation

\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\  \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\  \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}

Hence, the standard deviation of the given set of numbers is approximately 76.68 to 2 decimal places.

STEP 5: Calculate the First and third quartile

\begin{gathered} \text{IQR}=Q_3-Q_1 \\  \\ To\text{ get }Q_1 \\ We\text{ first arrange the data in ascending order} \\ \mathrm{Arrange\: the\: terms\: in\: ascending\: order} \\ 320,\: 321,\: 324,\: 360,\: 361,\: 366,\: 369,\: 372,\: 385,\: 397,\: 403,\: 454,\: 459,\: 475,\: 477,\: 482,\: 498,\: 513,\: 558,\: 559 \\ Q_1=(\frac{n+1}{4})th \\ Q_1=(\frac{20+1}{4})th=\frac{21}{4}th=5.25th\Rightarrow\frac{361+366}{2}=\frac{727}{2}=363.5 \\  \\ To\text{ get }Q_3 \\ Q_3=(\frac{3(n+1)}{4})th=\frac{3\times21}{4}=\frac{63}{4}=15.75th\Rightarrow\frac{477+482}{2}=\frac{959}{2}=479.5 \end{gathered}

STEP 6: Find the Interquartile Range

\begin{gathered} IQR=Q_3-Q_1 \\ \text{IQR}=479.5-363.5 \\ \text{IQR}=116 \end{gathered}

Hence, the interquartile range of the data is 116

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1 year ago
Find the length of MN.<br> A) 7 <br> B) 25 <br> C) 32 <br> D) 39
MrRissso [65]

Step-by-step explanation:

Answer C)

Explanation:

MN + NP = MP

MP = 39

Therefore, 4(x + 5) + 2x + 1= MP

So, 4(x + 5) + 2x + 1= 39

(4x + 20) + 2x +1 = 39

So, (4x + 2x) + (20 + 1) = 39

6x + 21 = 39

Addition changes to Subtraction

So, 6x = 39 - 21

6x = 18

Multiplication changes to Division

x= 18/6

x=3

Therefore MN = 4(x + 5)

So, 4(3 + 5) = 4(8)

4(8) = 32

Therefore, MN = 32

Hope this helps!

3 0
3 years ago
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