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Alex Ar [27]
4 years ago
12

Read the chemical equation. 2C2H2 + 5O2 → 4CO2 + 2H2O Which of the following statements would be correct if one mole of C2H2 was

used in this reaction? One mole of oxygen was used in this reaction. Five moles of oxygen were used in this reaction. Four moles of carbon dioxide were produced from this reaction. Two moles of carbon dioxide were produced from this reaction.
Chemistry
1 answer:
ss7ja [257]4 years ago
3 0

Answer:

Two moles of carbon dioxide were produced from this reaction.

Explanation:

2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

All hydrocarbons burn in excess air or oxygen to give carbondioxie and water.

The general balanced equation is given by:

Cₓ Hₐ + (x+a/4)O₂ → xCO₂ + (a/2) H₂O

If given 1 mole of C₂H₂,

We know that x = 2

a = 2

For (x+a/4)O₂, we would have:

(2+2/4) = 5/2 O₂

For xCO₂, we would have 2CO₂

For (a/2) H₂O, we would have:

(a/2) H₂O = (2/2)H₂O = H₂O

Therefore, for 1mole of C₂H₂, the complete equation is written as

C₂H₂ + 5/2O₂ → 2CO₂ + H₂O

We can conclude that,

5/2 mole of O₂ would be used

2 mole of CO₂ would be produced

1 mole of H₂O would be produced

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The vapor pressure of water at 50.0 c is 12.33 kpa. What is this value in millimeters of mercury?
kramer

Answer:

  • <u>92.48 mmHg</u>

Explanation:

You need the conversion factor to convert the value of 12.33 kPa to milimiters of mercury, mmHg.

The converstion factors are looked at tables, which today you can find in internet.

Since the conversions between kPa and atm and between atm and mmHg are more widely known, I will show the conversion using those relations:

  • 1 atm = 101.325 kPa
  • 1 atm = 760 mmHg

⇒ 101.325 kPa = 760 mmHg

Then, dividing both sides by 101.325 kPa you get the conversion factor:

  • 1 = 760 mmHg / 101.325 kPa

Now, multiply 12.33 kPa by that conversion factor:

  • 12.33 kPa × 760 mmHg / 101.325 kPa = 92.48 mmHg ← answer
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Which best explains how a single-celled organism can survive without other cells?
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Answer:

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Explanation:

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Read 2 more answers
calculate the molarity of MgCl2 in the following solution: 5.34 g of MgCl2 is dissolved and diluted to 214 mL of solution.
anyanavicka [17]
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf {0.262M }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>

Molarity is used to measure the concentration of a solution , so it is also as molar concentration. It is denoted as M or Mol/L

<u>We </u><u>are </u><u>given </u><u>that </u><u>:</u>

  • Weight of \sf MgCl_{2} = 5.34g
  • Volume of solution = 214 ml , or 0.214 L

The molar mass of magnesium chloride ( \sf MgCl_{2} ) is 95.21 g / mol

We can calculate the molarity of the solution by dividing the number of moles of solute by volume of solvent in liter ,i.e:

\quad\longrightarrow\quad \sf  {M = \dfrac{n}{V} } ‎ㅤ‎ㅤ‎ㅤ⸻( 1 )

<em>Where,</em><em> </em>

  • M = molarity
  • n = number of moles
  • V = Volume

We can calculate the number of moles by dividing the actual mass by its molar mass ,i.e:

\quad\longrightarrow\quad \sf { n = \dfrac{w}{m}}‎ㅤ‎ㅤ‎ㅤ‎⸻ ( 2 )

<em>W</em><em>here,</em>

  • n = number of moles
  • m = molar mass
  • w = actual mass

<u>Therefore</u><u>,</u>

\implies\quad \tt {n =\dfrac{w}{m} }

\implies\quad \tt { n =\dfrac{5.35\: g}{95.21\: g /mol}}

\implies\quad{\pmb{ \tt {n = 0.056 mol}} }

<u>P</u><u>utting </u><u>the </u><u>values </u><u>in </u><u>equation </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u>

\implies\quad \tt {M=\dfrac{n}{V} }

\implies\quad \tt { M =\dfrac{0.056\:mol}{0.214\:L}}

\implies\quad\underline{\pmb{ \tt { M = 0.262 \:M }}}

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Differences between selenium tellurium and polonium
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