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Marat540 [252]
3 years ago
14

An automobile gasoline tank holds 22 kg of gasoline. When the gasoline burns, 86 kg of oxygen is consumed and carbon dioxide and

water are produced. What is the total combined mass of carbon dioxide and water produced?
Chemistry
1 answer:
rosijanka [135]3 years ago
7 0
The law of conservation of mass states that mass is an isolated system and is neither created nor destroyed.

Applying this concept on a chemical reaction means that the total mass of reactants should be equal to the total mass of the products.

In this question, we have gasoline and oxygen as reactants and we have carbon dioxide and water as products.
Based on the law, the sum of the masses of oxygen and gasoline is equal to the sum of masses of carbon dioxide and water.
Therefore,
mass of carbon dioxide and water = 22 + 86 = 108 kg
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a sample of gas initially occupies 5.50 liter at a pressure of 0.750 atm at 13.0 C. what will the temperture change to 22.5 C an
sergey [27]

Answer:

The pressure will be 2.84 atm

Explanation:

The gas laws are a set of chemical and physical laws that allow us to determine the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

Boyle's law indicates that the volume is inversely proportional to the pressure: if the pressure increases, the volume decreases and if the pressure decreases, the volume increases. Boyle's law is expressed mathematically as:

P * V = k

On the other hand, Charles's law indicates that with increasing temperature, the volume of the gas increases and with decreasing temperature, the volume of the gas decreases. That is, they are directly proportional. This is expressed mathematically as:

\frac{V}{T} =k

Finally, the Gay-Lussac law says that at constant volume, the pressure of the gas is directly proportional to its temperature. Mathematically, it is expressed as:

\frac{P}{T} =k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T}=k

When you want to study two different states, an initial and a final one of a gas, you can use the following expression:

\frac{P1*V1}{T1}=\frac{P2*V2}{T2}

In this case:

  • P1= 0.750 atm
  • V1= 5.50 L
  • T1= 13 C= 286 K (being 0 C=273 K)
  • P2=?
  • V2= 1.50 L
  • T2= 22.5 C=295.5 K

Replacing:

\frac{0.750 atm*5.50 L}{286 K}= \frac{P2*1.50 L}{295.5 K}

Solving:

P2=\frac{295.5K}{1.50L} *\frac{0.750 atm*5.50 L}{286 K}

P2= 2.84 atm

<u><em>The pressure will be 2.84 atm</em></u>

8 0
4 years ago
What happens to the reactivity of nonmetals within a group from top of the group to the bottom?​
andreev551 [17]

As you go down a group, the atoms get bigger. The bigger the atom, the more unstable it is. The more unstable it is, the more reactive the atom will be. So, as you go down a group, the nonmetals will become more reactive.

6 0
3 years ago
In a 3.7- gram sample, there are______ atoms of gold
beks73 [17]
<h3>Answer:</h3>

1.1 × 10²² atoms Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.7 g Au

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

<u />3.7 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au} )(\frac{6.022 \cdot 10^{23} \ atoms \ Au}{1 \ mol \ Au} ) = 1.13121 × 10²² atoms Au

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

1.13121 × 10²² atoms Au ≈ 1.1 × 10²² atoms Au

7 0
3 years ago
I need help, I don't understand the question
rjkz [21]
The awnser is probably B
7 0
3 years ago
Can you explain what happens to resistance when voltage is increased?
Novay_Z [31]
Resistance is directly proportional to voltage so when you increase Voltage resistance will also increase in order to keep the rate of flow of charge (current) constant

Hope this helps!
4 0
3 years ago
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