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expeople1 [14]
3 years ago
13

How do I solve this operation

Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0
4 / ( 3 + 5i ) = [ 4( 3 - 5i)] / [ 3^2 - (5i)^2 ] = [ 4( 3 - 5i)] / 34 =  [ 2( 3 - 5i)] / 17 =
 6 / 17 - 10i / 17;
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If cosine theta equals negative square root of three over two and pi over two less than theta less than pi, what are the values
Natalka [10]
<h2>Answer:</h2>

The values of sinθ and tanθ are:

\sin \theta=\dfrac{1}{2}

and

\tan \theta=-\dfrac{1}{\sqrt{3}}=-\dfrac{\sqrt{3}}{3}

<h2>Step-by-step explanation:</h2>

It is given that:

\cos \theta=-\dfrac{\sqrt{3}}{2}

where

\dfrac{\pi}{2}

i.e. the angle θ lie in the second quadrant.

Also, we know that in the second quadrant sine and cosecant function is positive.

whereas cosine,secant, tangent and cotangent functions are negative.

Now, we know that:

\cos (\dfrac{5\pi}{6})=-\dfrac{\sqrt{3}}{2}

i.e. here

\theta=\dfrac{5\pi}{6}

Hence, we have:

\sin (\theta)=\sin (\dfrac{5\pi}{6})\\\\i.e.\\\\\sin \theta=\dfrac{1}{2}

Also,

\tan \theta=\dfrac{\sin \theta}{\cos \theta}\\\\i.e.\\\\\tan \theta=\dfrac{\dfrac{1}{2}}{\dfrac{-\sqrt{3}}{2}}\\\\i.e.\\\\\tan \theta=\dfrac{1}{-\sqrt{3}}\\\\i.e.\\\\\tan \theta=-\dfrac{1}{\sqrt{3}}

Now, on rationalizing we have:

\tan \theta=-\dfrac{\sqrt{3}}{3}

7 0
4 years ago
Read 2 more answers
The three squares that will form a right triangle are ...?
MAVERICK [17]

Answer:

Three squares that form right triangle:

A, E and C

Step-by-step explanation:

Area of E = 1^2 = 1

Area of A = 2.4^2 = 5.76

Area of C = 2.6^2 = 6.76

Area A + Area E = Area C

5 0
3 years ago
Solve the system of equations using the substitution method.
leva [86]

Answer:

The answer to your question is 1.- (37/2, -9/2)   2.-   g = 4  and h = 2

Step-by-step explanation:

Data

Equation 1     2x + 8y = 1

Equation 2       x = -3y + 5

Process

1.- Substitute equation 2 in equation 1

                    2(-3y + 5) + 8y = 1

Expand

                    -6y + 10 + 8y = 1

Solve for y

                     8y - 6y = 1 - 10

                             2y = -9

                               y = -9/2

2.- Substitute y in equation 2 to find x

                         x = -3(-9/2) + 5

Simplify

                         x = 27/2 + 5

                         x = 27/2 + 10/2

                         x = 37/2

Solution (37/2, -9/2)

2.-      

Equation 1      6g + 8h = 40

Equation 2     -6g + 2h = -20

Process

1.- Add both equations

Result

                       0   +  10h = 20

Solve for h

                                  h = 20/10

                                  h = 2

2.- Substitute h in Equation 1 to find g

                        6g + 8(2) = 40

Simplification

                       6g + 16 = 40

Solve for g

                               6g = 40 - 16

                               6g = 24

                                 g = 24/6

                                 g = 4

Solution   g = 4  and h = 2                

4 0
3 years ago
Read 2 more answers
Jerry walked a dog from 6:40 am to 7:30am . If he was paid $6 per hour how much did he earn
Usimov [2.4K]

Answer:

Amount Jerry earned is $5

Step-by-step explanation:

Jerry is paid $6 per hour.

First we need to find the number of hours he walked the dog.

From 6.40 am to 7.30 am we have 50 minutes. Jerry walked the dog for 50 minutes.

An hour has 60 minutes.

We need to find how much Jerry gets paid for a minute.

Amount paid for a minute     = \frac{$6}{60}

                                               =$0.1

Therefore,

Amount paid for 50 minutes = $0.1 * 50 minutes

                                                =$5

3 0
3 years ago
to prove that the triangles are congruent by asa which statement and reason could br used as part if the proof
Zielflug [23.3K]

Problem Example :

Given: HF || JK; HG ≅ JG

Prove: FHG ≅ KJG

Answer: A. ∠FGH ≅∠KGJ because vertical angles are congruent.


8 0
3 years ago
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