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Serga [27]
3 years ago
13

If cosine theta equals negative square root of three over two and pi over two less than theta less than pi, what are the values

of sin Θ and tan Θ?
sine theta equals negative one half, tangent theta equals square root of three over three
sine theta equals negative one half, tangent theta equals negative square root of three over three
sine theta equals one half, tangent theta equals negative square root of three over three
sine theta equals one half, tangent theta equals square root of three over three
Mathematics
2 answers:
Natalka [10]3 years ago
7 0
<h2>Answer:</h2>

The values of sinθ and tanθ are:

\sin \theta=\dfrac{1}{2}

and

\tan \theta=-\dfrac{1}{\sqrt{3}}=-\dfrac{\sqrt{3}}{3}

<h2>Step-by-step explanation:</h2>

It is given that:

\cos \theta=-\dfrac{\sqrt{3}}{2}

where

\dfrac{\pi}{2}

i.e. the angle θ lie in the second quadrant.

Also, we know that in the second quadrant sine and cosecant function is positive.

whereas cosine,secant, tangent and cotangent functions are negative.

Now, we know that:

\cos (\dfrac{5\pi}{6})=-\dfrac{\sqrt{3}}{2}

i.e. here

\theta=\dfrac{5\pi}{6}

Hence, we have:

\sin (\theta)=\sin (\dfrac{5\pi}{6})\\\\i.e.\\\\\sin \theta=\dfrac{1}{2}

Also,

\tan \theta=\dfrac{\sin \theta}{\cos \theta}\\\\i.e.\\\\\tan \theta=\dfrac{\dfrac{1}{2}}{\dfrac{-\sqrt{3}}{2}}\\\\i.e.\\\\\tan \theta=\dfrac{1}{-\sqrt{3}}\\\\i.e.\\\\\tan \theta=-\dfrac{1}{\sqrt{3}}

Now, on rationalizing we have:

\tan \theta=-\dfrac{\sqrt{3}}{3}

rosijanka [135]3 years ago
4 0

Answer:

sin θ = 1/2

tan θ = -√3 / 3

Step-by-step explanation:

cos θ = -√3 / 2, π/2 < θ < π

θ is in the second quadrant, so θ = 5π/6.

sin θ = 1/2

tan θ = sin θ / cos θ = -√3 / 3

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Answer: her sales for the month of May is $55000

Step-by-step explanation:

Let x represent her total sales for the month of May.

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3 years ago
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To calculate the distance between two points we use this formula:

\boxed{ \boxed{{d \:  =   \:  \sqrt{(x_2 \:  -  \: x_1)^{2} \:  +  \: (y_2 \:  -  \: y_1)^{2} } }}}

<h3>______________________</h3>

<h3>We organize the values:</h3>

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______________________

We apply the values already obtained to the formula to get the distance:

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\huge{\boxed{ \bold{2 \sqrt{17} \: units }}}

<h3><em><u>MissSpanish</u></em></h3>
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