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3 years ago

What is the absolute value of |-12|

Mathematics

1 answer:

aleksklad [387]3 years ago

4 0

Answer:

Step-by-step explanation:

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3 years ago

The width of the rectangle is 75% of its length. The length is 8 cm. What is the width of the rectangle?

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Given :

The length of the rectangle, l = 8 cm/

The width of the rectangle, w = 75% of 8 cm

$= \frac{75}{100} \times 8$

$=\frac{15}{20} \times 8$

= 0.75 x 8

= 6

Therefore, the width of the rectangle is 6 cm.

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3 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The vertices of a triangle are located at A (-5, -5), B (3, 4), C (3, -5). What is the perimeter of the triangle?

Veronika [31]

Answer:

34.6 units

Step-by-step explanation:

Given data

A (-5, -5), B (3, 4)

distance is

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((3 +5)^2 + (4 +5)^2)\\\\d= \sqrt((8)^2 + (9)^2)\\\\d= \sqrt(64 +81)\\\\d= \sqrt(145)\\\\d= 12.04$

B (3, 4), C (3, -5)

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((3 -3)^2 + (-5-4)^2)\\\\d= \sqrt((0)^2 + (-9)^2)\\\\d= \sqrt(0 +81)\\\\d= \sqrt(81)\\\\d= 9$

C (3, -5), A (-5, -5)

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-5 -3)^2 + (-5-5)^2)\\\\d= \sqrt((-8)^2 + (-10)^2)\\\\d= \sqrt(64 +100)\\\\d= \sqrt(164)\\\\d= 12.80$

Hence the perimeter

= 12.80+9+12.80

=34.6 units

3 0

3 years ago

What is the absolute value of |-12|​

What is the absolute value of |-12|