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Nana76 [90]
3 years ago
5

The formula for the area of a triangle is A = one-half b h. Which is the equivalent equation solved for h? StartFraction 2 A Ove

r b EndFraction = h One-half A b = h 2 A b = h StartFraction a Over 2 b EndFraction = h
Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0

Answer:

2A/b=h

Step-by-step explanation:

tensa zangetsu [6.8K]3 years ago
5 0

Answer:

StartFraction 2 A Over b EndFraction = h

Step-by-step explanation:

A =  \frac{1}{2}  \times b \times h \\  \\ 2A =  b \times h \\  \\  \huge \red{ \boxed{h =  \frac{2A}{b}}}  \\

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WILL MARK BRAINLIEST!!!!Which of the following relations is not a function?
Inessa [10]

Answer:

The third (C) option is the answer.

Because 4 is repeating in x coordinate,

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that is called <u>R</u><u>a</u><u>n</u><u>g</u><u>e</u><u>.</u>

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3 0
3 years ago
9 = -3 + n + 2n what does n equal ?
coldgirl [10]

Step-by-step explanation:

9=-3+n+2n

9+3=n+2n

12=3n

n=12/3

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5 0
3 years ago
Read 2 more answers
2
zhenek [66]

Answer:

Just substitute the values in!
(-5/9) + (-4/3) - 2/3 = - 5/9 - 12/9 - 6/9 = -23/9.

7 0
2 years ago
What are some benefits of solving equations graphically? What are some limitations?
Tasya [4]

Answer:

The required benefits and limitations are shown below:

Step-by-step explanation:

Consider the provided statement.

We need to determine the benefits and limitation of solving equations graphically.

Benefits:

1) By solving an equation graphically we can visually determine the solution of the equation.

2) The graphs provide clues that words and equations don't.

3) It helps to interpret data and to draw conclusions about mathematical relationships.

Limitations:

1) The intersecting point is the solution for an equation, and the solution may not be accurate as some equation may have decimal solutions.

2) Some times student interpret graphs inaccurately.

3) Also some equations can be difficult to graph because of their slopes.

4 0
3 years ago
Suppose that a die is rolled twice. What are the possible values that the following random variables can take on:(a) the maximum
andreyandreev [35.5K]

Answer and explanation:

Given : Suppose that a die is rolled twice.

The sample space form is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

To find : What are the possible values that the following random variables can take on

(a) The maximum value to appear in the two rolls;

The possible values are 1; 2; 3; 4; 5; 6.

b) The minimum value to appear in the two rolls;

The possible values are 1; 2; 3; 4; 5; 6.

c) The sum of the two rolls;

The possible values are 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12.

d) The value of the first roll minus the value of the second roll.

The possible values are -5; -4; -3; -2; -1; 0; 1; 2; 3; 4; 5.

5 0
3 years ago
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