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Minchanka [31]
2 years ago
6

You are making snap bags, you want each bag to have the same combination you have 75 carrots and 40 celery sticks and you want t

o use them all what is the greats number of bags you can make?
Mathematics
1 answer:
makkiz [27]2 years ago
4 0

Answer:

5 Bags

Step-by-step explanation:

There are 75 carrots and 40 celery sticks.

If we want each bag to have the same combination, the greatest number of bags we can make is determined by the Greatest common divisor of the two numbers.

To find the Greatest common divisor of 70 and 40

<u>Step 1:</u> Express each number as a product of its prime factors

  • 40=2 X 2 X 2 X 5
  • 75=3 X 5 X 5

<u>Step 2:</u> Pick each pair of common factors.

  • 40=2 X 2 X 2 X 5
  • 75=3 X 5 X 5

The only factor common to both pairs is 5.

Therefore, the Greatest common divisor of 70 and 40 is 5.

The greatest number of bags that can be made is 5.

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Question 11 (5 points)
KATRIN_1 [288]

Answer:

Yes

Step-by-step explanation:

Substitute the x value in the ordered pair for the x in the equation, or 2, and the y-value (6) in for y. So, 2 + 6 = 8, and this is true. Then do 3(2) - 6 = 0, which is also true.

6 0
2 years ago
A new baby elephant ate 23
sergejj [24]
If you multiply 23 by 12 you will get 276.
3 0
3 years ago
Read 2 more answers
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
Simplify this ratio 10 feet/30 inches
Deffense [45]

Answer:

1 feet/3 inches

7 0
2 years ago
the instructor has save $3500 and rents an apartment for $275 monthly. he believes the point 6, 1850 would be on the equation of
bazaltina [42]

Answer:Yes, he is correct

Step-by-step explanation:Plug 6 in as your x-value in the equation y=-275x+3500 and you will get y=1850

6 0
2 years ago
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