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Minchanka [31]
3 years ago
6

You are making snap bags, you want each bag to have the same combination you have 75 carrots and 40 celery sticks and you want t

o use them all what is the greats number of bags you can make?
Mathematics
1 answer:
makkiz [27]3 years ago
4 0

Answer:

5 Bags

Step-by-step explanation:

There are 75 carrots and 40 celery sticks.

If we want each bag to have the same combination, the greatest number of bags we can make is determined by the Greatest common divisor of the two numbers.

To find the Greatest common divisor of 70 and 40

<u>Step 1:</u> Express each number as a product of its prime factors

  • 40=2 X 2 X 2 X 5
  • 75=3 X 5 X 5

<u>Step 2:</u> Pick each pair of common factors.

  • 40=2 X 2 X 2 X 5
  • 75=3 X 5 X 5

The only factor common to both pairs is 5.

Therefore, the Greatest common divisor of 70 and 40 is 5.

The greatest number of bags that can be made is 5.

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There are 205 coins in a jar all of which are either nickles or quarters . The vaule of the coin in the jar is $31.85. if both o
Gnesinka [82]

Answer: There are 97 nickels and 108 quarters.

Step-by-step explanation:

Let x = Number of nickels, y = Number of quarters.

As per given,

x+y = 205    ...(i)

0.05x+0.25y = 31.85 ... (ii)    [1 nickel = $0.05, 1 quarter = $ 0.25]

Multiply (ii) by 20, we get

x+5y=637   ...(iii)

Eliminate (i) from (iii)

4y = 432

⇒ y = 108 [Divide both sides by 4]

Put value of y in (i), we get

108+x=205\Rightarrow\ x= 97

Hence, there are 97 nickels and 108 quarters.

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3 years ago
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The mean time it takes to walk to the bus stop is 8 minutes (with a standard deviation of 2 minutes) and the mean time it takes
11111nata11111 [884]
(a) Average time to get to school
Average time (minutes) = Summation of the two means = mean time to walk to bus stop + mean time for the bust to get to school = 8+20 = 28 minutes

(b) Standard deviation of the whole trip to school
Standard deviation for the whole trip = Sqrt (Summation of variances)

Variance = Standard deviation ^2
Therefore,
Standard deviation for the whole trip = Sqrt (2^2+4^2) = Sqrt (20) = 4.47 minutes

(c) Probability that it will take more than 30 minutes to get to school
P(x>30) = 1-P(x=30)
Z(x=30) = (mean-30)/SD = (28-30)/4.47 ≈ -0.45
Now, P(x=30) = P(Z=-0.45) = 0.3264
Therefore,
P(X>30) = 1-P(X=30) = 1-0.3264 = 0.6736 = 67.36%

With actual average time to walk to the bus stop being 10 minutes;

(d) Average time to get to school
Actual average time to get to school = 10+20 = 30 minutes

(e) Standard deviation to get to school
Actual standard deviation = Previous standard deviation = 4.47 minutes. This is due to the fact that there are no changes with individual standard deviations.

(f) Probability that it will take more than 30 minutes to get to school
Z(x=30) = (mean - 30)/Sd = (30-30)/4.47 = 0/4.47 = 0

From Z table, P(x=30) = 0.5
And therefore, P(x>30) = 1- P(X=30) = 1- P(Z=0.0) = 1-0.5 = 0.5 = 50%
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3 years ago
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