Answer:
2nd one.
Step-by-step explanation:
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
Answer:
Step-by-step explanation:
<u>Given equations:</u>
<u>Add together:</u>
- -8x + 8y + 3x - 8y = 8 - 18
- - 5x = - 10
Correct option is D
11^0 is 1.
11^2= 121
121/1= 121
Final answer: 121
Answer:
∠4 = 78°, assuming out measurements have been taken in degrees.
Step-by-step explanation:
If ∠2 = 8x + 10 and
∠4 = 42 + 6x
We will assume that x in both cases is represented by the same number, therefore, we will first need to solve for x. We will do so by equating both angle measurement expressions.
8x + 10 = 42 + 6x Take away 6x from both sides
2x + 10 = 42 Take 10 away from both sides to combine like terms
2x = 32 Divide both sides by 2 to isolate x
x = 16
Knowing x, we can solve for the measure of ∠4 by plugging in 16 for x
∠4 = 42 + 6x
∠4 = 42 + 6(6)
∠4 = 42 + 36
∠4 = 78°, assuming out measurements have been taken in degrees.
