Answer:
Step-by-step explanation:
If two values are inversely proportional, their product must be maintained. That way, if one value goes up, the other goes down by the same extent.
Therefore, if 
and 
vary inversely, their product will be the same for all values of 
and 
.
Let 
and 
as given in the problem. Substitute values:
Hence, the maintained product is 
.
Thus, we have the following equation:
Substitute 
to find the value of 
when :
The easiest way to figure out probability problem with small data sets is to write out your entire sample space then divide by the total:
Sample size = 6 * 6 = 36
S = {[1,1],[1,2],[1,3],[1,4],[1,5],[1,6],[2,1],[2,2],[2,3],[2,4],[2,5],[2,6],[3,1],[3,2],[3,3],[3,4],[3,5],[3,6],[4,1],[4,2],[4,3],[4,4],[4,5],[4,6],[5,1],[5,2],[5,3],[5,4],[5,5],[5,6],[6,1],[6,2],[6,3],[6,4],[6,5],[6,6]}
The only way to make a number combination that's even while 1 die is odd is to have 2 odd numbers.
{[1,1],[1,3],[1,5],[3,1],[3,3],[3,5],[5,1],[5,3],[5,5]}
This gives us 9 results.
The probability of this happening is 9/36 = 1/4 = 0.25
Now if we have to get a 6 with the product being at most 15 we know that the biggest number that 6 can be multiplied by is 2 which gives us 12.
We are left with 4 options:
{[1,6],[2,6],[6,1],[6,2]}
The probability of this happening is 4/36 = 1/9 = 0.1111...
