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Zigmanuir [339]

2 years ago

13

6. Which of the following equations has a slope of -2 and passes

1 answer:

Viefleur [7K]2 years ago

6 0

Answer:

y=-2x+2

Step-by-step explanation:

substitute either the x or y value into the equations, if you substitute x=3 and get back y=-4, the equation is correct

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Angelique makes beaded jewelry. The graph below shows the number of beads on varying cord lengths.

8_murik_8 [283]

Answer:

The Biden administration is extending a mask mandate for airplanes and transit for 15 days, the Centers for Disease Control and Prevention said Wednesday.

The mandate was set to expire after April 18, following a one-month extension announced in March. Airlines have required masks on planes since early in the pandemic in 2020, but the Biden administration made them mandatory in early 2021.

The CDC said it is monitoring the spread of omicron, including the BA.2 subvariant.

Step-by-step explanation:

23=4 3+4+7 1/2 4/7 8/2

6 0

2 years ago

What is the distance between the points (−7, 7) and (−7, 8) ? 1 unit 7 units 8 units 15 units Please Help I Will Mark Brainliest

k0ka [10]

√ 197

≈

14.03566884

So your answer should be 15 units

6 0

3 years ago

Read 2 more answers

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

So

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

2 years ago

PLS HELP ME WITH THHESE I GIVE ALL YALL BRAINLZESS

Olegator [25]

Answer:

1. R

2. Match the year with the price. For example, 2006 should have a line directly on 15.

3. A (The first number on each row is the second number multiplied by 4)

4. C

5. A

MAKE SURE TO DOUBLE-CHECK JUST IN CASE!

7 0

3 years ago

A 2-row table with 9 columns. The first row is labeled x with entries negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3

Margarita [4]

Answer:

x -4 -3 -2 -1 0 1 2 3 4

y -54 -20 -4 0 -2 -4 0 16 50

at 4 it is maximum .

maximum value=50

hope that helps

7 0

3 years ago

Read 2 more answers