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torisob [31]
3 years ago
5

In 1990, the GDP of Canada was $680 billion as measured in Canadian dollars, and the exchange rate was that $1 Canadian was wort

h 85 U.S. cents. In 2000, the GDP of Canada was $1000 billion as measured in Canadian dollars, and the exchange rate was that $1 Canadian was worth 69 U.S. cents.
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

cool fact! but whats the question?

Step-by-step explanation:

hope this helps

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If 50 grams of sweats cost $2.10,find the cost of 380 of sweats,giving your answer correct to the nearest 5 cent
Nezavi [6.7K]

Answer:

$15.95

Step-by-step explanation:

cost of 1 gram of sweet = $2.10 / 50 = 0.042

Cost of 380 g = 380 x 0.042 = $15.96

to the nearest 5 cent = 15.95

6 0
3 years ago
Tell me all the properties of algebra
Keith_Richards [23]

Answer:

  • Commutative Property of Addition.-  
  • 2 + 3 = 3 + 2
  •  Commutative Property of Multiplication.- ex. 5 × 7 = 7 × 5  
  • Associative Property of Addition.- ex.(2 + 3) + 6 = 2 + (3 + 6)  
  • Associative Property of Multiplication.- ex. (7 × 3) × 10 = 7 × (3 × 10)
  • Distributive Properties of Addition Over Multiplication- ex. 2 × (2 + 8) = 2 × 2 + 2 × 8  
  • (2 + 8) × 10 = 2 × 10 + 8 × 10
  • The reciprocal of a non zero real number a is 1/a.- ex. reciprocal of 5 is 1/5 and 5 × (1/5) = 1

Step-by-step explanation:

7 0
4 years ago
Indicate whether the lines are parallel, perpendicular, or neither.
Diano4ka-milaya [45]

Answer:

Perpendicular

Step-by-step explanation:

6 0
3 years ago
Question 2 of 10<br> 2 Points<br> Which of the following is the solution to 4|x+32 8?
Andreas93 [3]
Is there anything to choose from
6 0
3 years ago
Read 2 more answers
Select the graph that correctly represents ƒ(x) = –2(x + 4)2 – 1.Find the equation of the parabola with its focus at (3,4) and i
IgorC [24]

Answer:

Equation of parabola:  8*(y - 2) = (x - 3)^2

or

y = (1/8)*(x - 3)^2 + 2

Step-by-step explanation:

focus at (3,4) and its directrix y = 0.

Focus equation:  (h, k + c) = (3, 4)

Directrix equation  y =  k - c = 0

so  h = 3,   k + c = 4,   k - c = 0

Solve  the system :  k + c = 4 and k - c = 0

add the equations together:     k + c + k - c = 4 + 0

2k = 4

k = 2

so   k + c = 4,    2 + c = 4,   c = 2

4c (y - k) = (x -  h)^2

4*2 *(y - 2) = (x - 3)^2

8*(y - 2) = (x - 3)^2

3 0
3 years ago
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