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Rufina [12.5K]
4 years ago
10

What is the formula for the area of a triangle?

Mathematics
2 answers:
Nana76 [90]4 years ago
7 0

Answer:

\Large \boxed{\mathrm{\bold{C} }}

Step-by-step explanation:

We can find the area of the triangle when two sides are given and the angle in between the two sides.

\displaystyle A=\mathrm{\frac{1}{2} bc \cdot sinA}

b and c are the sides and A is the angle in between b and c.

Semmy [17]4 years ago
5 0

Answer:  c. (1/2) bc sin A

<u>Step-by-step explanation:</u>

You can find the area of a triangle using trigonometry if you know the lengths of two sides and the measure of the included angle using the following formula:

A=\dfrac{1}{2}ab\sin C

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What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success​ p? C
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Answer:

(D)E[ X ] =np.

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq  x\leq n

E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}

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E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}

Now,

x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)

Substituting,

E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}

Factoring out the n and one p from the above expression:

E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}

Representing k=x-1 in the above gives us:

E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}

This can then be written by the Binomial Formula as:

E[ X ] = (np) (p +(1 - p))^{n -1 }= np.

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