The intensity of a fire alarm that measures 125 dB loud is 268,337.29
<h3>Formula and expressions</h3>
Given the expression L=10 logI
where;
- L is the loudness
- I is the intensity of the sound.
Given the following parameters
L = 125dB
Substitute the given parameters into the following
L=10 logI
125 = 10logI
logI = 125/10
logI = 12.5
I = e^12.5
I = 268,337.29
Hence the intensity of a fire alarm that measures 125 dB loud is 268,337.29
Learn more on subject of formula here: brainly.com/question/657646
Set up two equations:
1st: P (for Price family) + J (for Jenkins family) = 45 hours
2nd: 20P + 35J = 1200 liters
Rewrite the first equation as P = 45 – J
Replace P in the second equation:
20(45-J) + 35J = 1200
Simplify:
900 -20J + 35J = 1200
900 +15J = 1200
Subtract 900 from both sides:
15J = 300
Divide both sides by 15:
J = 300/15
J = 20
Jenkins used theirs for 20 hours
Price used theirs for 45-20 = 25 hours.
Answer:
D(9, 1)
Step-by-step explanation:
A being the midpoint means its coordinates satisfy ...
A = (E + D)/2
Solving for D, we find ...
D = 2A -E
= 2(4, 5) -(-1, 9) = (2·4 +1, 2·5 -9)
D = (9, 1)
Answer:
It subtracts
Step-by-step explanation:
Answer:
3=111
Step-by-step explanation:
