1. Which of the given equations are linear?

The value of the digit in the hundreds placed in the number 653841 is 1/10 the value of the digit in the thousand place in which

kondor19780726 [428]

The complete question in the attached figure

we have that
the value of the digit in the hundreds place in the number 653,841 is---> 800

case A) 748,917
the value of the digit in the thousands place------> 8000
1/10 the value of the digit is-------> (1/10)*8000=800
800=800---------------> is ok

case B) 749,817
the value of the digit in the thousands place------> 9000
1/10 the value of the digit is-------> (1/10)*9000=900
900 is not 800

case C) 784,817
the value of the digit in the thousands place------> 4000
1/10 the value of the digit is-------> (1/10)*4000=400
400 is not 800

case D) 797,481
the value of the digit in the thousands place------> 7000
1/10 the value of the digit is-------> (1/10)*7000=700
700 is not 800

the answer is
the option A) 748,917

6 0

3 years ago

What is the difference?<br><br> 42−55<br><br> Enter your answer in the box.

nignag [31]

Answer:

-13

Step-by-step explanation:

42-55=-13

4 0

3 years ago

Read 2 more answers

Whats the median and the mode of the data 43,37,49,51,56,40,44,50,36,

nikklg [1K]

Answer:

Here I have uploaded the file with the answers

Step-by-step explanation:

6 0

3 years ago

Pls show work/steps for both questions

aleksklad [387]

Answer:

Step-by-step explanation:

$\frac{-5+2 \iota}{1+7 \iota} \times \frac{1-7 \iota}{1-7 \iota} \\=\frac{-5+35 \iota+2 \iota-14 \iota^2}{1-49 \iota^2} \\=\frac{-5+37 \iota-14(-1)}{1-49(-1)} \\=\frac{9+37 \iota}{50} \\=\frac{9}{50} +\frac{37}{50} \iota$

2.

domain is x²≤36

|x|≤6

-6≤x≤6

or [-6,6]

3 0

3 years ago

A toddler is allowed to dress himself on Mondays, Wednesdays, and Fridays. For each of his shirt, pants, and shoes, he is equall

avanturin [10]

Answer:

0.0286 = 2.86% probability that today is Monday.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Dressed correctly

Event B: Monday

Probability of being dressed correctly:

100% = 1 out of 4/7(mom dresses).

(0.5)^3 = 0.125 out of 3/7(toddler dresses himself). So

$P(A) = 0.125\frac{3}{7} + \frac{4}{7} = \frac{0.125*3 + 4}{7} = \frac{4.375}{7} = 0.625$

Probability of being dressed correctly and being Monday:

The toddler dresses himself on Monday, so (0.5)^3 = 0.125 probability of him being dressed correctly, 1/7 probability of being Monday, so:

$P(A \cap B) = 0.125\frac{1}{7} = 0.0179$

What is the probability that today is Monday?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0179}{0.625} = 0.0286$

0.0286 = 2.86% probability that today is Monday.

4 0

3 years ago

1. Which of the given equations are linear? ​

1. Which of the given equations are linear?