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mash [69]
3 years ago
15

Which one would it be?

Mathematics
1 answer:
Leni [432]3 years ago
6 0
C is the answer.
in the original function, when x=0, y=-1
in the new function, to make y=-1, x+3=0, x=-3. From the original 0 to -3 is a shift of 3 units to the left. 
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Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.
VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let \mu = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, H_0 : \mu \geq 30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, H_A : \mu < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean commute time = 27.6 minutes

            s = sample standard deviation = 19.6 minutes

            n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u>  =  \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }  ~ t_4_9_9

                                       =  -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0
3 years ago
A coffee supply store waits until the orders for its special coffee blend reach 100 pounds before making up a batch. Coffee sell
Daniel [21]
Let x represent the number of pounds of $10.75/lb coffee used in the mix.
.. 10.75x +3.25(100 -x) = 5.65*100 . . . . . . total cost of coffee blend
.. x(10.75 -3.25) = 100*(5.65 -3.25) . . . . . .separate x-terms from non-x terms
.. x = 240/7.5 = 32

32 pounds of $10.75/lb coffee should be used
68 pounds of $3.25/lb coffee should be used
7 0
3 years ago
What is the value of |–46| ?<br> A. -46<br> B. 46
vladimir1956 [14]
It would be positive 46
8 0
3 years ago
Read 2 more answers
Can anybody answer this? Please! I’ll mark you brainliest
labwork [276]

Problem 1: Plug in the given value into the function and evaluate.

f(x)=|3x|\\f(2)=|3(2)|\\f(2)=|6|\\f(2)=6

Problem 2: Solve the equation for y.

-7x+2y=8

add 7x to both sides to move it to the right side of the equation.

2y=7x+8

Divide both sides of the equation by 2 to get a single y variable on the left hand side.

\frac{2y}{2} =\frac{7x}{2} +\frac{8}{2} \\y=\frac{7}{2}x+4

Simplify the terms to get the the equation into slope-intercept form.

The slope of the line is \frac{7}{2}

I'm a unsure what Problem 3 is asking for sorry I hope the rest is helpful.

5 0
3 years ago
What is1\7 the speed of a cheetah?
klio [65]
1/7 the speed of a cheetah is 10 mph because an average cheetah can run 70 miles per hour. This means time to do some division. Envision  the denominator of 1/7 (7) as 70 and then the numerator (1) should be 10. Divide 70 by 7 should be 10. Hope this helps.
4 0
3 years ago
Read 2 more answers
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