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3 years ago

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What is the measure of angle A in the triangle below? Right triangle A B C is shown. Side B C has a length of 9 and hypotenuse A

B has a length of 18. 30° 45° 60° 90°

1 answer:

klasskru [66]3 years ago

8 0

Answer:

The answer is 30°

Step-by-step explanation:

I finished the test on edgen and passed

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SAT A bag contains 3 red marbles, 2 green

Alina [70]

Answer:

$\frac{1}{21}$

Step-by-step explanation:

refer to solution in picture

8 0

3 years ago

NEED HELP ASAP PLEASE

Ilya [14]

Answer:

see explanation

Step-by-step explanation:

Given

A = $\frac{1}{2}$ bh

a. substitute b = 6 and h = 5 into the formula

A = $\frac{1}{2}$ × 6 × 5 = $\frac{1}{2}$ × 30 = 15 units²

b.

Multiply both sides of the formula by 2

2A = bh, that is

bh = 2A ← divide both sides by b

h = $\frac{2A}{b}$ = $\frac{2(16)}{4}$ = $\frac{32}{4}$ = 8

c

Using

bh = 2A ← divide both sides by h

b = $\frac{2A}{h}$ = $\frac{2(12)}{4}$ = $\frac{24}{4}$ = 6

3 0

3 years ago

Solve x/3 = x+2/2. X=

Leni [432]

Answer:

I will assume that the term "x+2/2" is meant to be "(x + 2)/2)." Otherwise the equation would read (x/3) = x + 1

Step-by-step explanation:

(x/3) = (x + 2)/2

x = 3*(x+2)/2 [Multiply both sides by 3]

x = (3x + 6)/2

x = (3/2)x + 6/2

x - (3/2)x = 3

-0.5x = 3

x = -6

====================

Check:

Does (x/3) = (x + 2)/2 for x = -6?

(-6/3) = (-6 + 2)/2

-2 = -4/2

-2 = -2 YES

6 0

2 years ago

A piece of paper is 11 inches long and 8.5 inches wide. What is the area of the paper in square centimeters? (Please show work!)

goldenfox [79]

If you would like to know what is the area of the paper in square centimeters, you can calculate this using the following steps:

1 inch equals to 2.54 centimeters.

11 inches = 11 * 2.54 = <span>27.94 centimeters long
8.5 inches = 8.5 * 2.54 = </span><span>21.59 centimeters wide

11 inches long * 8.5 inches wide = 27.94 centimeters long * 21.59 centimeters wide = </span>27.94 * 21.59 = 603.22 square centimeters
<span>
The correct result would be </span>603.22 square centimeters.<span>
</span>

3 0

3 years ago

write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)

Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

From one of the rules of logarithm, we have that

$log_{x }yz= log_{x }y + log_{x }z$

Thus,

$log_{4 }6 \times a \times b$ becomes

$log_{4 }6 + log_{4 }a + log_{4 }b$

This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

$\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

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8 0

1 year ago