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4 years ago

Solve the system of two equations 2y=8 and 15y=2x-4

1 answer:

5 0

2y = 8
y = 8/2
y = 4

15y = 2x - 4
15(4) = 2x - 4
60 = 2x - 4
60 + 4 = 2x
64 = 2x
64/2 = x
32 = x

so x = 32 and y = 4....(32,4)

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the sale price of a spring break vacation package was $119.99 the travel agent said by booking early you saved $50 find the perc

andre [41]

Answer:

10%

Step-by-step explanation:

$179.99+$20=$199.99

$20/$199.99=0.1000

=10%

5 0

3 years ago

How much would 4.5 pounds of Skittles cost

Aleksandr-060686 [28]

Depends on the bag of Skittles you buy, but I assume you’re talking about a regular person 2.17 oz bag.

On the Target website, each 2.17 oz bag costs $0.89. 4.5 pounds is equivalent to 72 oz, so you would need about 33 bags of Skittles to have 4.5 pounds.

This means that $0.89 * 33 equals $29.37.

...

I put way too much effort into this...

6 0

4 years ago

Two college roommates have each committed to donating to charity each week for the next year. The roommates’ weekly incomes are

schepotkina [342]

Answer:

C. 5 weeks.

Step-by-step explanation:

In this question we have a random variable that is equal to the sum of two normal-distributed random variables.

If we have two random variables X and Y, both normally distributed, the sum will have this properties:

$S=X+Y\\\\\ \mu_S=\mu_X+\mu_Y=30+60=90\\\\\sigma_S=\sqrt{\sigma_X^2+\sigma_Y^2}=\sqrt{10^2+20^2}=\sqrt{100+400}=\sqrt{500}=22.36$

To calculate the expected weeks that the donation exceeds $120, first we can calculate the probability of S>120:

$z=\frac{S-\mu_S}{\sigma_S} =\frac{120-90}{22.36}=\frac{30}{22.36}=1.34\\\\P(S>120)=P(z>1.34)=0.09012$

The expected weeks can be calculated as the product of the number of weeks in the year (52) and this probability:

$E=\#weeks*P(S>120)=52*0.09012=4.68$

The nearest answer is C. 5 weeks.

6 0

3 years ago

The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5600. The distributi

pshichka [43]

Answer:

$E(\bar{x}) = 28520$

Standard error of mean = 689

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $28,520

Standard Deviation, σ = $5600

Mean of sampling distribution =

$E(\bar{x}) = \mu = 28520$

As per Central Limit Theorem, if the sample size is large enough, then the sampling distribution of the sample means follow approximately a normal distribution.

Sample size, n = 66

Since the sample size is large, we can use normal distribution for approximation.

Standard error of mean =

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{5600}{\sqrt{66}} = 689.31 \approx 689$

7 0

3 years ago

Tasha lists all the multiple of 3 from 3 to99. Tony lists all the multiples of 5 from 5 to100. What is the first number that is

IrinaVladis [17]

Answer:

Multiples of 3 = 3, 9
Multiples of 5 = 5, 10

Step-by-step explanation:

In a list of 3 to 99, the first multiple of 3 will be none other than 3 itself because when multiplied by 1, you get three.

The second number will be: 3 * 2 = 6

In a list from 5 to 100, the first multiple will be 5 with 5 being a multiple of itself when multiplied by 1.

Second number = 5 * 2 = 10

7 0

3 years ago