Answer:
$12
Step-by-step explanation:
42 - 6 = 36
36/3
12
Answer:
Step-by-step explanation:
r = 8.35 ft
area of circle = πr² = 69.7225π ft²
θ = 5π/9 radians
area of unshaded segment = r²(θ-sinθ)/2 ≅ 26.51 ft²
shaded region = 69.7225π - 26.51 ≅ 192.53 ft²
Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6