72.1 into a fraction is 72 and 1/10 :-)
Answer:
see attached for one possibility
Step-by-step explanation:
Graphs are <em>equivalent</em> if they have the same structure, but not necessarily the same labeling.
The graph given is one big loop with one of the edges doubled. An equivalent graph is one that can be drawn as one big loop with one of the edges doubled. The attachment shows one way to draw such a graph.
Renaming the vertices of the attached graph to A, C, D, B (clockwise from lower left) will make it <em>equal</em> to the given graph.
Answer:
The minimum sample size required is 1809 computer users.
Major obstacle to getting a good estimate of the population mean is
b) It is difficult to precisely measure the amount of time spent on the internet
Step-by-step explanation:
Minimum sample size can be found using the formula:
N≥
where
- N is the <em>computer users surveyed</em>
- z is the <em>corresponding z-score </em>for 95% confidence level
- s is the <em>standard deviation</em> of the population of monthly time spend on the internet
- E is the expected <em>margin of error</em> from the mean.
Here z=1.96, s=217 min. E=10 min. If we put these values in the formula we get
N≥
=1808.9≈ 1809
Major obstacle in the survey is that it is difficult to precisely measure the amount of time spent on the internet
Answer:
the answer is A, D, and F
Answer:
A. x¹/²
B. x¹/³
C. x¹/⁷
D. x⁵/²
E. x¹¹/³
F. 1 / x¹/⁴
G. 1 / x²/³
H. 1 / x⁹/²
Step-by-step explanation:
A. √x
Recall
√M = M¹/²
Therefore,
√x = x¹/²
B. ³√x
Recall
ⁿ√M = M¹/ⁿ
Therefore,
³√x = x¹/³
C. ⁷√x
Recall
ⁿ√M = M¹/ⁿ
Therefore,
⁷√x = x¹/⁷
D. √x⁵
Recall
√Mⁿ = Mⁿ/²
Therefore,
√x⁵ = x⁵/²
E. ³√x¹¹
Recall
ⁿ√Mᵃ = Mᵃ/ⁿ
Therefore,
³√x¹¹ = x¹¹/³
F. 1 / ⁴√x
Recall
ⁿ√M = M¹/ⁿ
Therefore,
1 / ⁴√x = 1 / x¹/⁴
G. 1 / ³√x²
Recall
ⁿ√Mᵃ = Mᵃ/ⁿ
Therefore,
1 / ³√x² = 1 / x²/³
H. 1 / √x⁹
Recall
√Mⁿ = Mⁿ/²
Therefore,
1 / √x⁹ = 1 / x⁹/²