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2 years ago

Solve for X 9x + 2 = 3 Give your answer as a fraction in its simplest form.

Mathematics

2 answers:

Alik [6]2 years ago

5 0

The answer would be x=1/9

kati45 [8]2 years ago

4 0

Answer:x=1/9

Step-by-step explanation:

1. subtract 2 from both sides

9x+2-2=3-2

2.simplify

9x=1

3.Divide both sides by 9

9x/9=1/9

4.simplify

x=1/9

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1/2 + 1/4 = how many quarters

Aleksandr [31]

Answer:

Step-by-step explanation:

1/2 = 0.5

1/4 = 0.25

1/2 + 1/4

= 0.5 + 0.25

= 0.75

= 75/100

= 3/4

Quarter is 1/4.

3/4 can be written as 3 x 1/4

Hence,

1/2 + 1/4 is 3 times 1/4

1/2 + 1/4 = 3 quarters.

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1 year ago

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3 years ago

What is 75% of 17000

Nikitich [7]

$\displaystyle 75\% \ of \ 17000 \\ \\ \\ \frac{75}{1\not0\not0} \cdot 170\not0\not0= \\ \\ \\ 75 \cdot 170= \\ \\ \\ 12.750 \\ \\$

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3 years ago

Marcie is going on a skiing vacation and is comparing the prices at two resorts, Alpine Fliers and Bob's Ski Bums.

spin [16.1K]

B. cost to ski per hour is more for Alpine, slope = 5$/hr. Slope for Bob's is 2.50$/hr. rate of increase is greater for Alpine.

E. Bob's has initial 10$ fee. Alpine is 0$ initial fee

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2 years ago

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Suppose the U.S. president wants an estimate of the proportion of the population who support his current policy toward revisions

kenny6666 [7]

Answer: a. 170 b. 752

Step-by-step explanation:

The formula to find the sample size is given by :-

$n= p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

, where p is the prior estimate of population proportion.

$z_{\alpha/2}$ = Two-tailed z-value for $\alpha$ (significance level).

E= Margin of error .

Given : Margin of error = 0.03

Confidence level = 90%=0.90

$\alpha=1-0.90=0.10$

By z-value table : $z_{\alpha/2}=z_{0.05}=1.645$

a) The president's political advisors estimated the proportion supporting the current policy to be : p= 0.06.

Required sample size :

$n= 0.06(1-0.06)(\dfrac{1.645}{0.03})^2$

$n=0.0564(3006.6944)$

$n=169.57756416\approx170$

∴ Required sample size = 170

b) If no prior estimate of population proportion is given , then we assume

p= 0.5

Required sample size :

$n= 0.5(1-0.5)(\dfrac{1.645}{0.03})^2$

$n=0.25(3006.6944)$

$n=751.6736\approx752$

∴ Required sample size = 752

3 0

3 years ago