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3 years ago

Am I right ? Because I need help with this please thanks.

Mathematics

1 answer:

bazaltina [42]3 years ago

7 0

to find the hypotenuse (or the ramp in question 4) you can use the equation

$a^{2} +b^{2} =c^{2}$

with a and b being the 3 feet and 9 feet and c being the unknown (ramp).

So if you plug 3 and 9 into the equation, it looks like this.

$3^{2} +9^{2} =c^{2}$

then square them.

$9+81=c^{2}$

simplify.

$90=c^{2}$

take the square root of both sides.

$\sqrt{90} = c$

$\sqrt{90}$ is approx. 9.5 so the answer would be H.

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The cake density is 0.454 ounce per cubic inch and the fair price is $0.20 per ounce. What should be a fair price for each cake?

aleksklad [387]

Answer:

price = x * 0.2

price = x * 0.454 * 0.2

Step-by-step explanation:

In this case we must know either the mass of the cake or its volume.

Given the case that we know the mass of the cake, it would be:

price = x * 0.2

where x is the mass of the cake in ounces, that is to say if for example a cake has a mass of 10 ounces, it would be:

price = 10 * 0.2 = 2

which means that each cake costs $ 2

Given the case of the volume, we must first multiply the density by this volume in order to calculate the mass and finally the price.

price = x * 0.454 * 0.2

where x is the volume of the cake in cubic inches, if for example the volume is 10 cubic inches it would be:

price = 10 * 0.454 * 0.2 = 0.908

which means that each cake costs $ 0.9

5 0

3 years ago

It is worth 50 points so please help

Vladimir [108]

Answer:

12 inches is the maximum length for each cloth because 60,48 and 72 are all multiples of 12.

you will have 5 pieces of blue cloth, 4 pieces of gold cloth and 6 pieces of white cloth.

4 0

3 years ago

Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (2, 3)

lozanna [386]

Standard equation of a circle: (x-h)² + (y-k)² = r² where (h, k) is the center and r is the radius. In the case of our equation here, (x-5)² + (y+3)² = 25, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = $\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Distance = $\sqrt{(-3-3)^2+(5-2)^2}$

Distance = $\sqrt{(-6)^2+3^2}$

Distance = $\sqrt{36+9}$

Distance = $\sqrt{45}\approx6.7082$

$6.7082>5,\ so\ (2,3)\ is\ on\ the\ \boxed{exterior}$