Am I right ? Because I need help with this please thanks.
1 answer:
to find the hypotenuse (or the ramp in question 4) you can use the equation
with a and b being the 3 feet and 9 feet and c being the unknown (ramp).
So if you plug 3 and 9 into the equation, it looks like this.
then square them.
simplify.
take the square root of both sides.
is approx. 9.5 so the answer would be H.
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let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>
for a pt (x,y) on line sx+ty=1, the minimum of
equals to
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hence m=75, n=67, p=3
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let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>
for a pt (x,y) on line sx+ty=1, the minimum of
equals to
smallest value happens at
so area is
hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145