2 years ago

What is the answer to this question. Please give me the answer ASAP

Mathematics

1 answer:

strojnjashka [21]2 years ago

6 0

still, if you have any doubt ask me!

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The width of a rectangle is 11 inches less than its length. Find the dimensions of the rectangle if the area is 80 squares inche

irina1246 [14]

Answer:

8r1000000

Step-by-step explanation:

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2 years ago

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What are the solutions of the equation (x-3)^2 + 2(x-3) -8 = 0

Mariulka [41]

Expand and simplify
(x-3) (x-3) +2(x-3) -8=0
(x-3+2)(x-3)-8=0
(x-1)(x-3)-8=0
x^2 -4x +3-8=0
x^2 - 4x -5=0
x^2 -5x +x-5=0
x(x-5)+x-5=0
(x+1)(x-5)=0
x= - 1, 5

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2 years ago

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I need to figure this out for a quiz in APEX. I can get the rest if I understand how to do this one.

KIM [24]

The answer is b
(-1,3,5)

Hope this helps!

8 0

2 years ago

If f(x) = -4x^2 - 6x - 1 and g(x) = -x^2 - 5x + 3, find (f + g)(x).

Flauer [41]

Answer:

-5 $x^{2}$ -11x+2

Step-by-step explanation:

-4 $x^{2} \\$ -6x-1- $x^{2}$ -5x+3=-5 $x^{2}$ -11x+2

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3 years ago

The cosine law

romanna [79]

$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-------------------------------\\\\$

$\bf \cfrac{sin(88^o)}{39.9}=\cfrac{sin(A)}{31}\implies \cfrac{31\cdot sin(88^o)}{39.9}=sin(A)
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=sin^{-1}\left[ sin(A) \right]
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=\measuredangle A
\\\\\\
50.93841^o\approx \measuredangle A\qquad thus\qquad \measuredangle C\approx 41.0619^o$

3 0

3 years ago