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lisov135 [29]
3 years ago
11

Solve for f, what is F-h=m ?

Mathematics
1 answer:
pogonyaev3 years ago
4 0
Ig the answer is: F=h+m
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What is the decimal multiplier to increase by 1.5 pls do the step by step explanation ineed help
satela [25.4K]

Answer:

Just an explanation so you can understand

Step-by-step explanation:

To increase, or decrease a number N, by a percentage X% we multiply N by a percentage multiplier (often just called multiplier).

We can calculate any percentage increase, or decrease, in three steps:

Step 1: write X% in decimal form. Remember, this is done by moving the number X back two decimal places.

Example: 5%=0.05, 12%=0.12, ... .

Step 2: Calculate the percentage multiplier by adding, or subtracting, the decimal found in step 1 to, or from, 1

For percentage increases: add the decimal to 1.

For percentage decreases: subtract the decimal from 1.

Step 3: multiply the number N by the multiplier, found in Step 2.

5 0
2 years ago
F(x) = x3 - 7 find(3)
ryzh [129]

____________________________________________________

Plug in 3 to x:

f(x) = 3³ - 7

Solve:

f(x) = 3³ - 7

f(x) = 3 · 3 · 3 - 7

f(x) = 9 · 3 - 7

f(x) = 27 - 7

f(x) = 20

____________________________________________________

4 0
3 years ago
Tomás Vega offers to pay $59 of the March cell phone bill Each of the other 4 members of the family agree to split the rest of t
adelina 88 [10]

it is $14.75 ....................

7 0
3 years ago
Find the simple interest rate needed in order for an investment of $2000 to grow to an account of $5000 in 3 years
Nutka1998 [239]

\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$5000\\ P=\textit{original amount deposited}\dotfill&\$2000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &3 \end{cases} \\\\\\ 5000=2000(1+r3)\implies \cfrac{5000}{2000}=1+3r\implies \cfrac{5}{2}=1+3r \\\\\\ 5=2+6r\implies 3=6r\implies \cfrac{3}{6}=r\implies 0.5=r\implies \stackrel{\textit{converting to percent}}{0.5\cdot 100\implies 50\%}

5 0
3 years ago
. An object dropped from a height of 200 meters has a height, h(t), in meters after t seconds have lapsed, such that h(t) = 200
Veronika [31]

Answer:

t(h)= (h-200)/-4.9

The time to reach a height of 50 meters is 30.6 seconds

Step-by-step explanation:

To express t as a function of height (h) we must transform the equation below:

h=200-4.9t

h-200=-4.9t

(h-200)/-4.9=t

t(h)= (h-200)/-4.9

To find the time to reach a height of 50 meters, we must replace this value on the new equation:

t(h)=50-200/-4.9

t(h)= 30.612

The time to reach a height of 50 meters is 30.6 seconds

8 0
3 years ago
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