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stellarik [79]
3 years ago
13

Look at photo (WITH THE PHOTO)

Mathematics
2 answers:
frez [133]3 years ago
8 0
The answer to that would be 3/8
padilas [110]3 years ago
5 0

Answer:

I got 11/12

Step-by-step explanation:

Because you would take 2/3 × 1/4

They don't have the same denominators so you have to find a multiple. 12 is a multiple of both 3 and 4. In order to get a denominator of 12 for 2/3 you would have to multiply 3 by 4 and 2 by 4 leaving you with 8/12. Then you would have to multiply 1 by 3 and 4 by 3 leaving you with 3/12. Then you add them giving you 11/12. Hope this helps

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Write the reflation ship between the value <br> of the given digits<br> 6s in 660
olga2289 [7]
Hello Srahman1183 i get how adjetated u must be feeling right now having to wait 6 days to get this answer im about to give u but whatever. The relationship between them istheyare both partof the powers of ten, the first 6 is inthe 100 place and the second 6 is in the 10 place, hope this helped
5 0
3 years ago
432566 10.5.623467.14,5<br><br> 4. What is the 1s (lower) quartile of the data set?
egoroff_w [7]

Answer:

I feel sorry that looks hard. see how do you like it. waiting for an answer and then someone finally answers. and there being a smart Butt

Step-by-step explanation:

4 0
3 years ago
The nth term of a sequence is 3n²-1
Anarel [89]

Answer: The number is 26.

Step-by-step explanation:

We know that:

The nth term of a sequence is 3n²-1

The nth term of a different sequence is 30–n²

We want to find a number that belongs to both sequences (it is not necessarily for the same value of n) then we can use n in one term (first one), and m in the other (second one), such that n and m must be integer numbers.

we get:

3n²- 1 =  30–m²

Notice that as n increases, the terms of the first sequence also increase.

And as n increases, the terms of the second sequence decrease.

One way to solve this, is to give different values to m (m = 1, m = 2, etc) and see if we can find an integer value for n.

if m = 1, then:

3n²- 1 =  30–1²

3n²- 1 = 29

3n² = 30

n² = 30/3 = 10

n² = 10

There is no integer n such that n² = 10

now let's try with m = 2, then:

3n²- 1 =  30–2² = 30 - 4

3n²- 1 = 26

3n² = 26 + 1 = 27

n² = 27/3 = 9

n² = 9

n = √9 = 3

So here we have m = 2, and n = 3, both integers as we wanted, so we just found the term that belongs to both sequences.

the number is:

3*(3)² - 1 = 26

30 - 2² = 26

The number that belongs to both sequences is 26.

6 0
2 years ago
Verify that each equation is an identity.<br><br> Show Work plzz!!
Pavlova-9 [17]

Answer:

Step-by-step explanation:

sin²x + cos²x = 1 ⇒ cos²x = 1 - sin²x

\frac{cos^2x}{cos^2x} = 1

3 0
2 years ago
If h(r) = 23r − 6, what is the value of h(-9)? Question 5 options: a) 0 b) 12 c) −623 d) -12
In-s [12.5K]

Answer:

-213

not in d option though check d question

Step-by-step explanation:

h(r) = 23r − 6

h(-9) = 23(-9) - 6

= -207 - 6

= -213

6 0
3 years ago
Read 2 more answers
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