What is the general form of the equation of a circle with its center at (-2,1) and passing through (-4,1)

Mathematics

1 answer:

cricket20 [7]2 years ago

7 0

Answer:

(x + 2)^2 + (y - 1)^2 = 2^2

Step-by-step explanation:

The equation of this circle is

(x + 2)^2 + (y - 1)^2 = r^2, and we are to determine the values of r^2 and r by substituting -4 for x and 1 for y:

(-4 + 2)^2 + (1 - 1)^2 = r^2, or:

(-2)^2 = r^2, or

4 = r^2

Then r = 2.

The desired equation is:

(x + 2)^2 + (y - 1)^2 = 2^2

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3 years ago

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fomenos

Answer: B. 84 in²

Step-by-step explanation:

Divide the area into two regions: a rectangle and a trapezoid (depicted in the attached photo).

Find the area of the rectangle:

Area of a rectangle=length*width

Area of rectangle=(5 in)( 10 in)

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Next, calculate the area of the trapezoid: