Question

What is the general form of the equation of a circle with its center at (-2,1) and passing through (-4,1)

Answer 1

Answer:

(x + 2)^2 + (y - 1)^2 = 2^2

Step-by-step explanation:

The equation of this circle is

(x + 2)^2 + (y - 1)^2 = r^2, and we are to determine the values of r^2 and r by substituting -4 for x and 1 for y:

(-4 + 2)^2 + (1 - 1)^2 = r^2, or:

(-2)^2                        =  r^2, or

4 = r^2

Then r = 2.

The desired equation is:

(x + 2)^2 + (y - 1)^2 = 2^2