What is the general form of the equation of a circle with its center at (-2,1) and passing through (-4,1)
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
Answer:
(x + 2)^2 + (y - 1)^2 = 2^2
Step-by-step explanation:
The equation of this circle is
(x + 2)^2 + (y - 1)^2 = r^2, and we are to determine the values of r^2 and r by substituting -4 for x and 1 for y:
(-4 + 2)^2 + (1 - 1)^2 = r^2, or:
(-2)^2                        =  r^2, or
4 = r^2
Then r = 2.
The desired equation is:
(x + 2)^2 + (y - 1)^2 = 2^2
 
                                
             
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