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2 years ago

Anyone solve these questions

Mathematics

1 answer:

Law Incorporation [45]2 years ago

8 0

Answer:

(5) 84° and 96° ; (6) 40° and 50°

Step-by-step explanation:

5) Supplementary angles are in the ratio 7 : 8

So 7x + 8x = 180°

15x = 180

x = 180/15

x = 12

The angles are 7x = 7 * 12 = 84° ; 8x = 8 * 12 = 96°

6) Complementary angles are in the ratio 4 : 5

So 4x + 5x = 90°

9x = 90

x = 90/9

x = 10

The angles are 4x = 4 * 10 = 40° ; 5x = 5 * 10 = 50°

You might be interested in

The larger leg of a right triangle is 3cm longer than its smaller leg. The hypotenuse is 6cm longer than the smaller leg. how ma

Natalka [10]

$b=a+3\\
c=a+6\\
a^2+b^2=c^2\\\\
a^2+(a+3)^2=(a+6)^2\\
a^2+a^2+6a+9=a^2+12a+36\\
a^2-6a-27=0\\
a^2-9a+3a-27=0\\
a(a-9)+3(a-9)=0\\
(a+3)(a-9)=0\\
a=-3 \vee a=9\\
$

The length can't be negative, so the answer is 9 cm.

5 0

2 years ago

Read 2 more answers

I need help solving systems of linear equations by substitution. {4x+3y=14 3x-2y=2

Sauron [17]

Answer:

A) 4x+3y=14

B) 3x-2y=2

We multiply equation A) by (2/3)

A) (8/3) x +2y = 28/3 then we add this to equation B)

B) 3x-2y=2

5 (2/3) x = 11 (1/3)

x = 2

A) 4 * 2 + 3 y = 14

A) 3y = 6

y = 2

Step-by-step explanation:

4 0

2 years ago

Jay, Kay, and Ray found themselves far apart when they stopped for lunch while walking in a field. Jay could see Kay, then turn

MariettaO [177]

Hi There! :)

Jay, Kay, and Ray found themselves far apart when they stopped for lunch while walking in a field. Jay could see Kay, then turn through 75th, and couldsee Ray. Jay could see Ray, then turn through 50th amd see Jay. Ray could see Jay, the turn through 55th, and see Kay. Which two were the farthest apart?

A. Kay and Ray
B. Jay and Kay
C. Ray and Jay
D. Kay and Ray were the same distance apart as Ray and Jay

I believe it's A. Kay and Ray

8 0

3 years ago

Read 2 more answers

#25 need help ASAP!!!!!

miv72 [106K]

Answer:

You need to find the surface of each area and sum them up.

Step-by-step explanation:

You will need the surface area for each side.

So 2 up-bottom, 2 left-right and two front-back

2*(4*3) + 2*(2*4) + 2(3*2)

2*12 + 2*8 + 2*6