In order to have infinitely many solutions with linear equations/functions, the two equations have to be the same;
In accordance, we can say:
(2p + 7q)x = 4x [1]
(p + 8q)y = 5y [2]
2q - p + 1 = 2 [3]
All we have to do is choose two equations and solve them simultaneously (The simplest ones for what I'm doing and hence the ones I'm going to use are [3] and [2]):
Rearrange in terms of p:
p + 8q = 5 [2]
p = 5 - 8q [2]
p + 2 = 2q + 1 [3]
p = 2q - 1 [3]
Now equate rearranged [2] and [3] and solve for q:
5 - 8q = 2q - 1
10q = 6
q = 6/10 = 3/5 = 0.6
Now, substitute q-value into rearranges equations [2] or [3] to get p:
p = 2(3/5) - 1
p = 6/5 - 1
p = 1/5 = 0.2
Answer:
0.5<
Step-by-step explanation:
5/10<5+65/10+100<65/100
=5/10<5+65/10+100<65/100
=1/2<1+13/2+20<13/20
=1/2<14/22<
Answer:
Step-by-step explanation:
charge q1 is placed at x = 1.90 m and the charge q2 is placed at y = 1.15 m
here, the charge enclosed in a sphere is zero as the radius of sphere is 0.625 m which is less than the x = 1.90 m and y = 1.15 m. So by the Gauss's theorem,
where q is the charge enclosed, as the charge enclosed is zero so the electric flux is zero.
Answer:
ummm- i dont really know this one- but i think the answer is 0
Step-by-step explanation:
Answer:
60^3 + 8a -5
Step-by-step explanation:
Like opposite of 5 is 5×-1 = -5,
Opposite of -60³ - 8a +5 is:
-(-60³ - 8a +5)
60³ + 8a - 5
