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Eva8 [605]
3 years ago
8

Is the circumference of all circles about 3 times greater than their diameters. and why?

Mathematics
1 answer:
stira [4]3 years ago
8 0

Answer:

<h2>Yes the circumference is about times greater than their diameters</h2>

Step-by-step explanation:

We will approach this problem by doing a check

Say the diameter of a circle is 4 cm

Hence the radius is 3 cm

We know that the circumference is C=2\pi r

C=2*3.142*2= 12.57cm

The circumference is about 3 time bigger than the diameter

Let us try another case say the diameter is 6 cm

The radius is 3 cm

C=2*3.142*3= 18.85cm

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Ich bin milly ,ich bin schön, du bist schön und klug!;)) <br> Wo ist deine Liebe zu dir?
ira [324]

Answer:

What?

Step-by-step explanation:

3 0
2 years ago
find the value of a and b for which the system of equations has infinitely many solutions : 2x + 3y = 7 ; (a-b)x + (a+b)y = 3a +
hodyreva [135]

Answer:

a= 5    and   b=1

Step-by-step explanation:

To solve, we will follow the steps below:

2x + 3y = 7

(a-b)x + (a+b)y = 3a + b - 2​

We should note that since it has infinitely many solutions then,

\frac{a_{1} }{a_{2} }   =  \frac{b_{1} }{b_{2} }  = \frac{c_{1} }{c_{2} }

Hence

2/a-b  =  3/a+b   =     7/3a +b-2

2/a-b  =  3/a+b

cross-multiply

3(a-b) = 2( a+b)

open the bracket

3a - 3b = 2a + 2b

collect like term

3a - 2a = 2b + 3b

a = 5b  -------------------------------------------(1)

Similarly

3/a+b   =     7/3a +b-2

cross-multiply

7(a+b)  = 3(3a+b -2)

7a + 7b = 9a + 3b -6

take all the variables to the left-hand side of the equation

7a - 9a+ 7b-3b =   -6

-2a + 4b = -6 ---------------------------------(2)

but a = 5b

substitute a= 5b in equation (2)   and solve for b

-2(5) + 4b = -6

-10  +  4b  = -6

add 10 to both-side of the equation

-10  + 10+ 4b  = -6+10

4b = 4

divide both-side of the equation by 4

b = 1

substitute b= 1 in equation (1)

a = 5b

a =5(1)

a=5

Therefore,   a= 5    and   b=1

8 0
3 years ago
Use the discriminant to describe the roots of each equation. Then select the best description. x2 - 6x + 9 = 0 double root real
Digiron [165]

ax^2 + bx+c =0

discriminant b^2-4ac

(-6)^2 - 4(1) *(9)

36-36 = 0

if the discriminant >0  it has 2 real roots

                              = 0  it has 1 root of multiplicity 2

                             < 0 has 2 imaginary root

x^2 - 6x + 9 = 0

(x-3)(x-3)=0

root is 3 multiplicity 2

Answer : double root real and rational

4 0
3 years ago
Determine if the sequence is arithmetic. If it is, find the common difference.
mr_godi [17]

Answer:

In an arithmetic sequence, the difference between any two consecutive terms must always be the same number, which is known as the common difference.

So we just need to take different pairs of consecutive terms and see if their difference is always the same:

1) The differences are:

32 - 35 = -3

29 - 32 = -3

26 - 29 = -3

So yes, this is an arithmetic sequence and the common difference is -3

2) The differences are:

-23 - (-3) = -20

-43 - (-23) = -20

-63 - (-43) = -20

This is an arithmetic sequence, and the common difference is -20

3) The differences are:

-64 -(-34) = -30

-94 -(-64) = -30

-124 -(-94) = -30

This is an arithmetic sequence and the common difference is -30

4) The differences are:

-40 -(-30) = -10

-50 - (-40) = -10

-60 - (-50) = -10

This is an arithmetic sequence and the common difference is -10

5) The differences are:

-9 - (-7) = -2

-11 - (-9) = -2

-13 - (-11) = -2

This is an arithmetic sequence, and the common difference is -2

6) The differences are:

14 - 9 = 5

19 - 14 = 5

24 - 19 = 5

This is an arithmetic sequence, and the common difference is 5.

7 0
2 years ago
$2500 was invested for 3 years and earned $450 in intrest. Fine the rate of intrest
Aleksandr-060686 [28]
$450/3 = $150/year was earned
8 0
3 years ago
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