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raketka [301]
3 years ago
5

A high school coach wants to buy new athletic shorts for the 15 members of the basketball team.The coach must spend less than $2

00 on the shorts. Which inequality represent how many pairs of shorts,s,the coach can buy?
Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer: 15s

Step-by-step explanation:

Given : A high school coach wants to buy new athletic shorts for $15 per member of the basketball team.

Let s represents the number of shorts .

Then, the cost of s shorts = 15 s   (1)

The coach must spend less than $200 on the shorts.

i.e. 15s   [From (1)]

Hence, the  inequality represent how many pairs of shorts,s,the coach can buy

15s

Divide both sides by 15 , we get

s

i.e. the cost of each short must be less than $13.33.

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four families go to the cinema. the reid family take 2 adults and 2 children for £18 ; the mghee family take 1 senior, 2 adults
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Answer:

\pounds 26.50

Step-by-step explanation:

Let

x = cost for one adult

y = cost for one child

z = cost for one senior.

<u>The Reid family:</u>

take 2 adults and 2 children and paid 2x+2y that is \pounds 18, so

2x+2y=18

<u>The Mghee family:</u>

take 1 senior, 2 adults and 1 child and paid x+2x+y that is \pounds 18.50, so

x+2x+y=18.50

<u>The Griffiths family:</u>

take 1 senior and 3 adults and paid z+3x that is \pounds 19.50, so

z+3x=19.50

You get the system of three equations:

\left\{\begin{array}{l}2x+2y=18\\ \\z+2x+y=18.50\\ \\z+3x=19.50\end{array}\right.

From the first equation:

2y=18-2x\\ \\y=9-x

From the third equation:

z=19.50-3x

Substitute them into the second equation:

19.50-3x+2x+9-x=18.50\\ \\-3x+2x-x=18.50-19.50-9\\ \\-2x=-10\\ \\2x=10\\ \\x=5

Then

y=9-5=4\\ \\z=19.50-3\cdot 5=19.50-15=4.50

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the cost for one adult is \pounds 5

the cost for one child is \pounds 4

the cost for one senior is \pounds 4.50

<u>The Linton family</u> takes 1 senior, 2 adults and 3 children and paid

\pounds 4.50+2\cdot \pounds 5+3\cdot \pounds 4=\pounds 26.50

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