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2 years ago

Solve using the quadratic formula

Mathematics

1 answer:

dangina [55]2 years ago

4 0

X=0

Hope you have a great day

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Harman [31]

Answer: 65

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2 years ago

Read 2 more answers

In this picture, m<4=m<5=

djverab [1.8K]

Answer:

In the picture above.

Step-by-step explanation:

Using some identities for solution

I hope that it's a clear solution.

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2 years ago

I need these 2 questions answered please.

Sav [38]

The area of the circle is 28 ft square.

The area of the triangle is 30 ft square.

Step-by-step explanation:

1) The area of the circle= π*r^2

where π= 3.14(default value) and "r" is the radius of the circle.

Here, Radius of the circle(r)= 3 ft

Area = 3.14*3*3

= 28.26 ft sq.= 28 ft sq(rounded to the nearest whole number)

2) The triangle has the base= 10 feet and height= 6 feet

The Area of the triangle= 1/2(b)(h)

where "b" is the base and "h" is the height of the triangle.

Substitute b=10 and h=6 ,

Area of triangle= 1/2(10 ft)(6 ft)= 60/2= 30 feet sq.

5 0

3 years ago

Ben is going to rotate a figure in Quadrant IV 90 counterclockwise. In which Quadrant should be image be

fomenos

The answer would be quadrant 1.

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3 years ago

The sum of two polynomials is â€"yz2 â€" 3z2 â€" 4y 4. If one of the polynomials is y â€" 4yz2 â€" 3, what is the other polynomi

gtnhenbr [62]

The sum of polynomials involves adding the polynomials

The other polynomial is $y^3 -y^2+ 4y - 1$

The sum of the polynomials is given as:

$Sum = y^3 + 3y^2 + 4y - 4$

One of the polynomials is given as:

$P = 4y^2 - 3$

Represent the other polynomial with Q.

So, we have:

$P +Q =Sum$

Substitute the expressions for P and Sum

$4y^2 - 3 +Q =y^3 + 3y^2 + 4y - 4$

Make Q the subject

$Q =y^3 + 3y^2 -4y^2+ 4y - 4 +3$

Evaluate like terms

$Q =y^3 -y^2+ 4y - 1$

Hence, the other polynomial is $y^3 -y^2+ 4y - 1$