To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
V=(pi)(2r^2)(h)
V=4(pi)(r^2)(h)
V=4(100 aka the old volume)
V=400cm^3
Answer:
I think the answer is 46 because 9 + 23 + 7 + 7 = 46.
Step-by-step explanation:
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The number of grams is 20 grams
Let x represent how many grams of a 15 percent alcohol solution
15%x+30%.40/x+40
=25%
0.15x+0.4.30=0.25 (x+40)
0.15x+12=0.25x+10
0.15x-0.25x=10+12
-0.1x=-2
x=-2/-0.1
x=20
Inconclusion The number of grams is 20 grams
Learn more here:
brainly.com/question/24750329
Answer:
<em>Grades to be scored in 3rd exam = 88</em>
Step-by-step explanation:
Given that average of 3 numbers is 85.
First two numbers are 81 and 86.
To find:
3rd number so that average is 85
Solution:
Let the third number = 
Formula for average is:
Here, sum of numbers = 
Total count of numbers = 3
<em>Grades to be scored in 3rd exam = 88</em>
