3 years ago

Find the area 10.4 in 6 in 6 in 6 in

Mathematics

1 answer:

LekaFEV [45]3 years ago

7 0

24in and have a good day

You might be interested in

Multiply (1.2 ⋅ 1028) ⋅ (3 ⋅ 10−19). Express the answer in scientific notation.

iris [78.8K]

The answer would be A. 3.6 × 10^9

5 0

3 years ago

Read 2 more answers

Anyone that can help me with this?

Flauer [41]

Okay. 10×5=50cm^2 is the area of the rectangle
The height of the triangle is (18-10)=8cm
So (8×5)÷2=20cm^2
50+20=70cm^2 is the area of the composite shape

8 0

3 years ago

Read 2 more answers

This is pretty easy! Please help!❤️❤️❤️

vladimir1956 [14]

99m I think I not sure though

6 0

3 years ago

Jenna is writing a check to her vehicle registration office for $100.42. How should she pull out this amount in the "written amo

Angelina_Jolie [31]

Answer:

100 42/100

Step-by-step explanation: you put the change as a fraction

3 0

3 years ago

If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?

Irina18 [472]

Answer:

Step-by-step explanation:

Hello,

If $X=x^2$ it becomes

$X^3-289X^2-X+289=(X^2-1)(X-289)$

and $289=17^2$

$X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)$

So,

$x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)$

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

3 0

3 years ago