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Nataly [62]
3 years ago
15

Can someone help me with this

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0
3*(-4)^2 - (-4) = 52
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Below is the five-number summary for 144 hikers who recently completed the John Muir Trail (JMT). The variable is the amount of
bearhunter [10]

Answer:

The IQR is given by:

IQR = Q_3 -Q_1 = 28-18= 10

If we want to find any possible outliers we can use the following formulas for the limits:

Lower= Q_1 - 1.5 IQR

Upper= Q_3 + 1.5 IQR

And if we find the lower limt we got:

Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3

Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43

So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

Q1: 18 days

Median: 21 days

Q3: 28 days

Maximum: 56 days

The IQR is given by:

IQR = Q_3 -Q_1 = 28-18= 10

If we want to find any possible outliers we can use the following formulas for the limits:

Lower= Q_1 - 1.5 IQR

Upper= Q_3 + 1.5 IQR

And if we find the lower limt we got:

Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3

Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43

So then the left boundary for this case would be 3 days

6 0
3 years ago
Hey ! Can anyone help me with this please ? Thank you so much .
castortr0y [4]

9514 1404 393

Answer:

  x = 57

Step-by-step explanation:

Where parallel lines are crossed by a transversal, all obtuse angles are congruent and supplementary to all acute angles, which are also congruent.

  x = 180 -123

  x = 57

6 0
2 years ago
Which expression has a positive quotient?
Dimas [21]
A because two negatives make a positive
4 0
3 years ago
Read 2 more answers
Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra
Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize x^2-\frac13 as yet another difference of squares:

x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)

And if you're working over the field of complex numbers, you can go even further. For instance,

x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)

But I think you'd be fine stopping at the first result,

x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}

6 0
3 years ago
Angela invests 2,550 at 3% interest compounded annually. What will be the balance in the account after 1.5 years?
marin [14]

answer my question then i'll answer yours


Which sentence uses a conjunctive adverb correctly?

The kite was hopelessly tangled in electrical wires, still, the little girl's father struggled to get it down.<span>The kite was hopelessly tangled in electrical wires; still, the little girl's father struggled to get it down. 
</span>
6 0
3 years ago
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