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3 years ago

What would be the first step to slove the system of equations 2x-9y=6 and 4x-3y=-7

2 answers:

5 0

If there are choices, then you need to choose the correct choice, but if there are no choices, then one correct answer is to multiply the first equation by -2 and add it to the second equation to eliminate x and solve for y.

andrew11 [14]3 years ago

4 0

The first step varies depends on what method you want to use to solve the system of equations.
If it is me, my first step would be either doubling the first equation so the coefficients of x in both equations equal to each other, or tripling the second equation so the coefficient of y in both equations is set equal.

2x-9y=6
4x-3y=-7

3(second euation) =12x-9y=-7

second equation subtract the first equation
10x=-13
x=-13/10

Then we can plug x in any of the two original equations and solve for y which i got to be -19/15

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Let f(x) = 3x^2 – 8x + 5 and let g(x) = 2x – 8. Find

fenix001 [56]

Answer:

B. 3x² – 10x + 13

Step-by-step explanation:

given:

f(x) = 3x² – 8x + 5

g(x) = 2x – 8

f(x) - g(x)

= (3x² – 8x + 5) - (2x – 8)

= 3x² – 8x + 5 - 2x + 8

= 3x² – 10x + 13

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3 years ago

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3 years ago

Q1. Find the measure of angle 1. Show your work.

OlgaM077 [116]

Answer:

1. 110°

2. 139°

Step-by-step explanation:

1. 180° in a triangle

180 - 40 - 30 = 110°

2. 180° in a triangle

angles on a straight line add up to 180°

180 - 64 - 75 = 41°

180 - 41 = 139°

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3 years ago

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3 years ago

Write the equation in standard form for the circle with center (0, – 10) and radius 6.

Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: $(x-h)^2+(y-k)^2=r^2$

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

$(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36$

So, equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

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3 years ago