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3 years ago

Find the point on the y-axis that is equidistant from the points (-3,0) and (3,6).

Mathematics

2 answers:

kodGreya [7K]3 years ago

7 0

Answer:

(0,3)

Step-by-step explanation:

$M=(\frac{-3+3}{2} ),(\frac{0+6}{2} )$

= $(\frac{0}{2} ,\frac{6}{2} )$

=(0,3)

IceJOKER [234]3 years ago

3 0

Answer:

(0,3)

Step-by-step explanation:

first write coordinates of y-axis (0,y)
then apply mid point formula

y=(y1+y2)/2
y=(0+6)/2
y=6/2
y=3

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31. Each day, Talisa exercises by first

GaryK [48]

Answer:

Step-by-step explanation:

Given the following :

Laps - - - - - - - - 5 - - - 6 - - - 7 - - - 8 - - - 9

Total time - - - 25 - - 28 - - 29 - - 30 - - 32

Using online graphing tool:

The y - axis named dependent variable represents the total time taken.

The x-axis, represents the number of laps.

The equation of the trend line attached to the plot is in the form :

y = mx + c

y = 1.6x + 17.6

Where y = total time taken

x = number of laps

m = 1.6 = gradient of the line (change in y / change in x)

C = 17.6 = intercept (whee the trndline intersects the y-axis).

5 0

3 years ago

One root of the quadratic equation x^2 − 2x + m = 0 is 9. If the other root is n, what is n−m?

mote1985 [20]

$9^2-2*9+m=0\\
\\
81-18+m=0\\
\\
m=-63$

$x^{2} -2x-63=0\\
\\
\Delta=(-2)^2-4.1.(-63)=4+252=256\\
\\
x=\frac{2 \pm 16}{2}\\
\\
x_1=\frac{18}{2}=9\\
\\
n=x_2=\frac{-14}{2}=-7\\
\\
n-n=-7-(-63)=-7+63=56$

4 0

3 years ago

Plz I really need help with this problem<br> Find the are of the shaded region

Nat2105 [25]

Answer:

$379.69 \: {ft}^{2}$

Step-by-step explanation:

Area of the shaded region = Area of the square with side 25 ft - Area of the semicircle with radius (25/2) = 12.5 ft.

$= {(25)}^{2} - \frac{1}{2} \times \pi \times {(12.5)}^{2} \\ \\ = 625 - \frac{1}{2} \times 3.14 \times 156.25 \\ \\ = 625 - 245.3125 \\ \\ = 379.6875 \: {ft}^{2} \\ \\ = 379.69 \: {ft}^{2}$