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Ket [755]
3 years ago
6

In Triangle ABC, DE is parallel to AC and DE = 10. Find the length of AC if DE is a midsegment of triangle ABC. Enter your answe

r as a number.

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0
AC = 20 because of DE = 1/2 AC then 10+10=20
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How to simplify -12 divided by 3•(-8+(-4) to the seccond power-6)+2
ehidna [41]
-12/3<span>•(-8(-4)^2-6)+2   Original Equation
-12/3</span><span>•(-8+16-6)+2      Simplify the (-4)^2
-12/3</span><span>•(2)+2                  Simplify everything inside the equation
-8+2                              Using PEMDAS, you multiply -12/3</span><span>•(2)
-6                                  You add from there</span>
7 0
3 years ago
-21 , 55 , -97 , 34 , 56 , -83 least to greatest?
FinnZ [79.3K]

Answer:

the answer is -97, -83, -21, 34, 55, 56

Step-by-step explanation:

The simple way to put it is negitives are backwards, the bigger the number the lesser it gets. So always put the highest negitive as least, hope this helps!

5 0
3 years ago
Read 2 more answers
Use the midpoint formula to find the midpoint between the following 2 points<br> R(6,-6) and G (4,2)
Likurg_2 [28]

Answer:

(5,-2)

Step-by-step explanation:

6+4=10

10/2=5

-6+2=-4

-4/2=-2

3 0
3 years ago
Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0
3 years ago
Explain how you could use the Associative Property of Multiplication
Degger [83]

Answer:

5/(6*2*1/2)

Step-by-step explanation:

No matter where you put the parenthesis it stays the same answer. :)

8 0
3 years ago
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