What is the conjugate of square root of 8 minus square root of nine

Mathematics

1 answer:

Gwar [14]3 years ago

7 0

(√8 -√9)* = √8 +√9 . . . . . where * signifies the conjugate

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Hi. I'm kind of confused on this question. Pls help

Musya8 [376]

Answer:

B is the awnser.

Step-by-step explanation:

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Roll a dice if the dice shows 6 tick the box marked yes.

maksim [4K]

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Question 1 (33 points)

myrzilka [38]

Answer:

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Step-by-step explanation:

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defon

Heya!!!

Answer to your question:

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Hope it helps ^_^

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3 years ago

Lim x->1+( sin(1-x)-(e^(x-1))+1)/ lnx

BigorU [14]

We're given the one-sided limit,

$\displaystyle\lim_{x\to1^+}\frac{\sin(1-x)-e^{x-1}+1}{\ln(x)}$

Evaluating the limand directly at <em>x</em> = 1 gives the indeterminate from

(sin(1 - 1) - exp(1 - 1) + 1) / ln(1) = 0/0

so we can potentially solve the limit by applying L'Hopital's rule. Doing so gives

$\displaystyle\lim_{x\to1^+}\frac{\sin(1-x)-e^{x-1}+1}{\ln(x)}=\lim_{x\to1^+}\frac{-\cos(1-x)-e^{x-1}}{\frac1x}=\frac{-\cos(0)-e^0}{\frac11}=\boxed{-2}$

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