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3 years ago

I know it’s not 5 please help.

Mathematics

1 answer:

antoniya [11.8K]3 years ago

7 0

It’s 2 because you plug in “x+1” as y into the the first equation then solve for x.

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Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

Which set of lengths are not the side lengths of a right triangle? (A-28, 45, 53) (B-13, 84, 85) (C-36, 77, 85) (D-16, 61, 65) [

nikklg [1K]

Side lengths 16, 61, and 65 are not part of a right triangle.

A right triangle's sides should follow this formula, C being the largest number:

$a^{2} + b ^{2} = c^{2}$

$16^{2} = 256$

$61^{2} = 3721$

$65^{2} = 4225$

256 + 3721 = 3977

$3977 \neq 4225$

6 0

2 years ago

HELP ME PLEASE WITH THIS QUESTION!!!!!!!!!!!

allochka39001 [22]

I think you have to divide

7 0

3 years ago

Which of the following functions best describes this graph?

jok3333 [9.3K]

<h3>Answer: Choice C</h3>

Explanation:

The x intercepts or roots are x = 3 and x = 5, which lead to the factors x-3 and x-5 respectively.

Multiplying out those factors gets us this:

(x-3)(x-5)

x(x-5)-3(x-5)

x^2-5x-3x+15

x^2-8x+15

8 0

2 years ago

Solve 9x – 3 > 2x + 11. Show each step of your work please.

Y_Kistochka [10]

Let's do this step by step:
Our objective is to find out x.

First, we have to take the '-3' to the right side, and put it next to the 11. When we do this its operation reverses, so it becomes 11 + 3, which is 14.
So we have 9x > 2x + 14.
Then we do the same to the numbers with X, but this time we take the number from the right side to the left. So 2x to the left (reversed) becomes 9x-2x which is 7x.
So 7x > 14
Now let's simplify, 14/7 = 2
so x = 2

6 0

3 years ago

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