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Harlamova29_29 [7]
2 years ago
5

1/a+2/b+3/c; Express as a single fraction.

Mathematics
2 answers:
Anika [276]2 years ago
8 0
Answer: (bc+2ac+3ab)/(abc)
UNO [17]2 years ago
8 0

For this case we must express as a single fraction the following expression:\frac {1} {a} + \frac {2} {b} + \frac {3} {c}

We have that the common denominator of the three fractions is given by: abc

So, to express as a fraction we divide abc by each denominator and multiply by each numerator, obtaining:

\frac {bc + 2ac + 3ab} {abc}

Answer:

\frac {bc + 2ac + 3ab} {abc}

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kifflom [539]

Hey there,

To solve this problem, let us first define what is mean and median. Mean is the average of all the numbers in the data set while the median is the number in the middle of the data set in ascending order. If we create a box plot for the data of Rome and New York, we can see that there is an outlier in the data for New York. Since New York has an outlier, so the mean is not a good representation on the central tendency of the data. The mean is skewed (distorted) by the outlier. So in this case it is better to use the median. While the Rome data is nice and symmetrical, it does not seem to have an outlier,  so we can use the mean for this data set.

Therefore the answer is:

The Rome data center is best described by the mean. The New York data center is best described by the median

Hoped I Helped

6 0
3 years ago
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. Find the domain and range of y=(3-x)2<br><br>-8.​
HACTEHA [7]

Domain : ( – ∞ ,  ∞ ) , {x/x ∈ R }

Range : [ 0 ,  ∞ ) , { y/y ⩾ 0 }

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Please can someone tell me whether my answer to the question is right? The topic is simultaneous equations.
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X should equal -13.33. Y is correct, 13.33
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HELPPPPP MEEEEEEE NOWWWWWWWWW HELPPPPPPPPPPPP
meriva

\huge{\mathbb{\tt{ANSWER:}}}

<h2>TRUE </h2>

\huge{\mathbb{\tt{SOLUTION↓}}}

See the file attached (photo) and analyze it! ☺️ , Have a Great Day! ☺️✨❤️

#CarryOnLearning

#LetsEnjoyTheSummer

<h3>→XxKim02xX</h3>

6 0
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2. Find the general relation of the equation cos3A+cos5A=0
mars1129 [50]
<h2>Answer:</h2>

A=\frac{\pi}{8}+\frac{n\pi}{4}or\ A=\frac{\pi}{2}+n\pi

<h2>Step-by-step explanation:</h2>

<h3>Find angles</h3>

cos3A+cos5A=0

________________________________________________________

<h3>Transform the expression using the sum-to-product formula</h3>

2cos(\frac{3A+5A}{2})cos(\frac{3A-5A}{2})=0

________________________________________________________

<h3>Combine like terms</h3>

2cos(\frac{8A}{2})cos(\frac{3A-5A}{2})=0\\\\  2cos(\frac{8A}{2})cos(\frac{-2A}{2})=0

________________________________________________________

<h3>Divide both sides of the equation by the coefficient of variable</h3>

cos(\frac{8A}{2})cos(\frac{-2A}{2})=0

________________________________________________________

<h3>Apply zero product property that at least one factor is zero</h3>

cos(\frac{8A}{2})=0\ or\ cos(\frac{-2A}{2})=0

________________________________________________________

<h2>Cos (8A/2) = 0:</h2>

<h3>Cross out the common factor</h3>

cos\ 4A=0

________________________________________________________

<h3>Solve the trigonometric equation to find a particular solution</h3>

4A=\frac{\pi}{2}or\ 4A=\frac{3\pi}{2}

________________________________________________________

<h3>Solve the trigonometric equation to find a general solution</h3>

4A=\frac{\pi}{2}+2n\pi \ or\\ \\ 4A=\frac{3 \pi}{2}+2n \pi\\ \\A=\frac{\pi}{8}+\frac{n \pi}{4\\}

________________________________________________________

<h2>cos(-2A/2) = 0</h2>

<h3>Reduce the fraction</h3>

cos(-A)=0

________________________________________________________

<h3>Simplify the expression using the symmetry of trigonometric function</h3>

cosA=0

________________________________________________________

<h3>Solve the trigonometric equation to find a particular solution</h3>

A=\frac{\pi }{2}\ or\ A=\frac{3 \pi}{2}

________________________________________________________

<h3>Solve the trigonometric equation to find a general solution</h3>

A=\frac{\pi}{2}+2n\pi\ or\ A=\frac{3\pi}{2}+2n\pi,n\in\ Z

________________________________________________________

<h3>Find the union of solution sets</h3>

A=\frac{\pi}{2}+n\pi

________________________________________________________

<h2>A = π/8 + nπ/4 or A = π/2 + nπ, n ∈ Z</h2>

<h3>Find the union of solution sets</h3>

A=\frac{\pi}{8}+\frac{n\pi}{4}\ or\ A=\frac{\pi}{2}+n\pi ,n\in Z

<em>I hope this helps you</em>

<em>:)</em>

5 0
2 years ago
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