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Gre4nikov [31]
3 years ago
7

if Noah finishes the race in 20seconds and Elliot finishes the race in 1/2 the time as Noah, how many seconds does it take Ellio

t to finish the race?
Mathematics
1 answer:
Dominik [7]3 years ago
4 0

Answer:

10 seconds

Step-by-step explanation:

Elliot finishes the race in 1/2 of 20 sec or 10 sec

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Emir made $182 in interest by placing $700 in a savings account with simple interest for 2 years. What was the interest rate?
Pavlova-9 [17]

Answer:

7.69230%

R=I/P×T

R=$182/$700×2

R=182/1400

R=91/700

=7.69230%

6 0
3 years ago
10 pts<br> Point K (-2,-3) is translated (x + 5, y-7). What are the coordinates K?
Nady [450]
The answer is (3,-10)
4 0
3 years ago
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ICE Princess25 [194]

Answer:

a

Step-by-step explanation:

6 0
3 years ago
In a recent​ year, an author wrote 169 checks. Use the Poisson distribution to find the probability​ that, on a randomly selecte
grigory [225]
We should first calculate the average number of checks he wrote per day.  To do that, divide 169 by 365 (the number of days in a year) and you get (rounded) 0.463.  This will be λ in our Poisson distribution.  Our formula is
P(X=k)= \frac{ \lambda ^{k}-e^{-\lambda} }{k!}.  We want to evaluate this formula for X≥1, so first we must evaluate our case at k=0.  
P(X=0)= \frac{0.463 ^{0}-e ^{-0.463} }{0!} \\ = \frac{1-e ^{-0.463} }{1} =0.3706
To find P(X≥1), we find 1-P(X<1).  Since the author cannot write a negative number of checks, this means we are finding 1-P(X=0).  Therefore we have 1-0.3706=0.6294.
There is a 63% chance that the author will write a check on any given day in the year.<em />
8 0
3 years ago
If records indicate that 15 houses out of 1000 are expected to be damaged by fire in any year, what is the probability that a wo
nordsb [41]

Answer: 0.01708

Step-by-step explanation:

Given : If records indicate that 15 houses out of 1000 are expected to be damaged by fire in any year.

i.e. the probability that house damaged buy fire in a year : p=\dfrac{15}{1000}=0.015

The formula for binomial distribution is given by :-

^{n}C_xp^x(1-p)^{n-x}

Now, the probability that a woman who owns 14 houses will have fire damage in 2 of them in a year (put n=14 and x=2), we get

^{14}C_2(0.015)^2(1-0.015)^{14-2}\\\\=\dfrac{14!}{2!(14-2)!}(0.015)^2(0.985)^{12}\\\\=0.0170788520518\approx0.01708

Hence, the required probability = 0.01708

4 0
3 years ago
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