Answer:
the first system
Step-by-step explanation:
if you put each equation into slope-intercept form you get:
y ≤ -3/5x + 2
y < x - 5
y < -5x + 6
if you place all three equations into a graphing calculator the result will look identical to the graph
Answer:
x = 12
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
-2(x - 4) = -16
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute -2: -2x + 8 = -16
- Isolate <em>x</em> term: -2x = -24
- Isolate <em>x</em>: x = 12
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitute: -2(12 - 4) = -16
- Subtract: -2(8) = -16
- Multiply: -16 = -16
Here we see that -16 does indeed equal -16.
∴ x = 12 is a solution of the equation.
Hello this should be your graph here
Hello,
Use the factoration
a^2 - b^2 = (a - b)(a + b)
Then,
x^2 - 81 = x^2 - 9^2
x^2 - 9^2 = ( x - 9).(x + 9)
Then,
Lim (x^2- 81) /(x+9)
= Lim (x -9)(x+9)/(x+9)
Simplity x + 9
Lim (x -9)
Now replace x = -9
Lim ( -9 -9)
Lim -18 = -18
_______________
The second method without using factorization would be to calculate the limit by the hospital rule.
Lim f(x)/g(x) = lim f(x)'/g(x)'
Where,
f(x)' and g(x)' are the derivates.
Let f(x) = x^2 -81
f(x)' = 2x + 0
f(x)' = 2x
Let g(x) = x +9
g(x)' = 1 + 0
g(x)' = 1
Then the Lim stay:
Lim (x^2 -81)/(x+9) = Lim 2x /1
Now replace x = -9
Lim 2×-9 = Lim -18
= -18
